- #1
deltapapazulu
- 84
- 12
Zill DE text says (y-x)dx+(4xy)dy=0 can be rewritten as:
4xy'+y=x
Am I missing something? I got 4xyy'+y=x instead.
Very rarely have I ever required starting a thread in a forum to resolve something as seemingly trivial as this but I just want to verify whether this is a typo or not.
Here are the steps I took:
The original is: (y-x)dx+(4xy)dy = 0
From there I got:
(4xy)dy=(x-y)dx
then
(4xy)dy/dx = x-y
then
(4xy)y'+y=x or 4xyy'+y=x
4xy'+y=x
Am I missing something? I got 4xyy'+y=x instead.
Very rarely have I ever required starting a thread in a forum to resolve something as seemingly trivial as this but I just want to verify whether this is a typo or not.
Here are the steps I took:
The original is: (y-x)dx+(4xy)dy = 0
From there I got:
(4xy)dy=(x-y)dx
then
(4xy)dy/dx = x-y
then
(4xy)y'+y=x or 4xyy'+y=x