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mslena79
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1. There is a block parallel and touching a vertical wall, a force F is applied at a 40 deg. angle from -x,-y. the weight of the block is 88.9N. The coefficient of static friction between the block and the wall is 0.560.
a) what is the minimum force F required to prevent the block from sliding down the wall?
b) what is the minimum force F required to start the block moving up the wall?
3.a) Fs(max)=(0.560)(88.9N)=49.8N
Fy=88.9N-49.8N=39.1N
Fx=(39.1N)/(cos(40))=51.0N
[tex]\sqrt{39.1^2+51.0^2}[/tex]=F
F=64.3N
b) 88.9N +49.8 N=138.7N=Fy
Fx=(138.7N)/(cos(40))=181.06N
[tex]\sqrt{138.7^2+181.06^2}[/tex]=F
F=228N
a) what is the minimum force F required to prevent the block from sliding down the wall?
b) what is the minimum force F required to start the block moving up the wall?
Homework Equations
3.a) Fs(max)=(0.560)(88.9N)=49.8N
Fy=88.9N-49.8N=39.1N
Fx=(39.1N)/(cos(40))=51.0N
[tex]\sqrt{39.1^2+51.0^2}[/tex]=F
F=64.3N
b) 88.9N +49.8 N=138.7N=Fy
Fx=(138.7N)/(cos(40))=181.06N
[tex]\sqrt{138.7^2+181.06^2}[/tex]=F
F=228N