How can f(x, y) be defined on y=x for a continuous function?

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In summary, the function f: ℝ² → ℝ : (x,y) |--> {{x^3-y^3}\over{x-y}} can be defined on the line y=x as f(x, y)= x^2+ xy+ y^2= 3x^2 to create a continuous function.
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Alexx1
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How can the function

f: ℝ² → ℝ : (x,y) |--> [tex]{{x^3-y^3}\over{x-y}}[/tex] if x ≠ y

be defined on the line y=x so that we get a continuous function?Is this correct?: If x=y --> f=0
 
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No. Did you have any reason at all for thinking that?

For [itex]x- y\ne 0[/itex]
[tex]\frac{x^3- y^3}{x- y}= x^2+ xy+ y^2[/itex]

As long as x is NOT equal to y, that function is the same as [itex]x^2+ xy+ y^2[/itex]. The function will be continuous on the line the line x= y, if we define [itex]f(x, y)= f(x, x)= x^2+ xy+ y^2= x^2+ x^2+ x^2= 3x^2[/itex], not "0".
 
  • #3
HallsofIvy said:
No. Did you have any reason at all for thinking that?

For [itex]x- y\ne 0[/itex]
[tex]\frac{x^3- y^3}{x- y}= x^2+ xy+ y^2[/itex]

As long as x is NOT equal to y, that function is the same as [itex]x^2+ xy+ y^2[/itex]. The function will be continuous on the line the line x= y, if we define [itex]f(x, y)= f(x, x)= x^2+ xy+ y^2= x^2+ x^2+ x^2= 3x^2[/itex], not "0".

Thank you very much!
 

FAQ: How can f(x, y) be defined on y=x for a continuous function?

What is continuous extension?

Continuous extension is the process of extending or expanding a scientific theory or concept over time. It involves continuously building upon existing knowledge and making new discoveries to further understand a particular subject or phenomenon.

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