Infinite well Definition and 72 Threads

Hi so that I can get the help for the specific problem I am working on I will set the question up and include all the steps that I can get and work out. The end question will be about quantized energy levels. This is for a maths module. I am working on infinite wells and particularly on a...

Imagine an infinite well with two distinct regions in it. In Region A, potential energy is zero, however, Region B has a potential energy level of U0. A particle with energy E>U0, is inside the well. In which region is the wavenumber k of the particle larger? A or B? This was a problem my...

Homework Statement A particle is initially in the ground state of a one-dimensional infinite square well extending from x=0 to x = L/2. Its wave function, correctly normalized, is given by \psi (x) = \dfrac{2}{\sqrt{L}} \sin{(\dfrac{2 \pi x}{L})}} for 0 \leq x \leq L/2 Suddenly, the right hand...

Homework Statement The well is set up exactly like this https://www.physicsforums.com/showthread.php?t=397977&highlight=potential+barrier+inside+an+infinite+square+well. It is basically a infinite potential well with a barrier in the center. Basically I've got solutions for regions 1, 2...

Homework Statement Well I thought this problem was easy, turned in the homework and got it wrong. My prof is hard to get help from, so hopefully someone here can help me out. A particle is in a one dimensional infinite square well with walls at x=0 and x=L. At time t=0 the well is expanded to...

I can solve the infinite will with length a. But what happens when the coordination is shifted, namely: V(x)=0,\frac{ -a}{4}<x<\frac{3a}{4} I use the usual solution: \psi=Asin(kx)+Bcos(kx) Now when I apply the first boundary condition: \psi(\frac{ -a}{4})=\psi(\frac{3a}{4})=0 I can't get rid...

Homework Statement I need to find the mean square distance between the 2 particles. Before I can do that, I need the expectation of x_1^2 and x_2^2 , then x_1x_2. I an on the first part and got stuck.Homework Equations <X_1^2>=\int_0^L \int_0^L x_1^2 |\psi_{n,m}(x_1,x_2)|^2 dx_1dx_2 where...

Homework Statement A particle of mass m is in the lowest energy (ground) state of the infinite potential energy well (V(x)=0 for 0<x<L, and infinite elsewhere) At time t=0 the wall located at x=L is suddenly pulled back to a position at x=2L. This change occurs so rapidly that...

Hi all, I've been looking at the problem of two interacting electrons in a 1D infinite well and wanted to run my conclusions past other people to see if I'm on the right track. The potential is 0 from x=0 to x=1 and infinite outside of this. The 1 particle solutions to this potential are...

Homework Statement http://img379.imageshack.us/img379/1864/screenshothw4pdfapplicamd7.png Homework Equations H|\psi > = E_n |\psi > The Attempt at a Solution About part 1 of the question: I can find the eigenfunctions of psi_1 by comparing coefficients with the well known...

Homework Statement Find the expectation value: <(x1-x2)^2> for two non-interacting particles in the infinite square well. If one is in state \psi_1( n \neq l) and the other in state \psi_n find the expectation value for a) distinguishable particles, b) bosons, c) fermions Homework...

Homework Statement Need to find the probability density of a ground state in an infinite square well. Homework Equations Ground State psi(x) = Asin(Bx), don't want to look up the constants, don't think they are relevant anyway. The Attempt at a Solution Took the derivative of...

Homework Statement The time-independent Schrodinger equation solutions for an infinite well from 0 to a are of the form: \psi_n(x) = \sqrt{2/a} \sin (n \pi x/ a) If you move the well over so it is now from -a/2 to a/2, then you can replace x with x-a/2 and get the new equations right? If I...

I have an infinite well from -a to with a particle in its ground. The initial wavefunction is then \psi(x) = u_1^+(x;a) = cos(\pi x/ 2a)/\sqrt{a} for |x| < a. In order to get the wavefunction for this particle when box that is instantaneously expanded to [-b,b] should I apply Fourier...

This may sound very basic, but I've just learned about the potential well with infinite barriers at +a and -a and I had a doubt. If we measure the momentum of a particle inside the well, it collapses to an eigenstate of the momentum operator, so, the uncertainty will be zero. Accordingly, the...

Homework Statement Problem 1. If I had a wavefunction: \Psi(x,0) = A(\psi_1(x) + \psi_2(x)) What is the probability of getting E1 or E2 as your energy? Problem 2 You have a wavefunction: \Psi(x,0) = Ax; 0<= x <= a/2 ; A(a-x); a/2<= x <= a What is the probability that an energy...

Homework Statement I need to show that a particle in an infinite potential well in the nth energy level, obeys the uncertainty principle and also show which state comes closest to the limit of the uncertainty principle. This means i have to calculate <x>, <x^2>, <p> and <p^2>Homework...

I am just trying to get my head round how this models the electron bound to an atom. I don't understand why the potential is zero in the well What physical case corresponds to the condition that V(x)=0 for all values of x? Thanks

What does it mean to find eigenvalues and eigen functions of an infinite well?

Hello all, I just ran across this forum thanks to google and decided to register and ask for some help on my homework! I'm in 2nd year university and we have a problem set due on Friday and this is the question on it: I started to do part a) but it seems very wrong. What I did was try to...

as title, the electron's interaction is coulomb force. 1.is it unsolvable?(exact solution) 2.will computer simulation be the only way to work it out? thanks a lot,dude

You're not understading: Let me give you all my work to alleaviate any confusion. Show that A = (2/L)1/2 &psi(x) = A Sin(&pi x/L) &psi2(x) = A2 Sin2(&pi x/L) [inte]0L &psi2dx = 1 A2[inte]0L Sin2(&pi x/L) dx = 1 Actually... I forgot to resubsitute... BTW: I only use a...