- #36
Hurkyl
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In 1874 Georg Cantor postulated that there is more than one level of infinity. The lowest level he called "countable infinity" and higher levels he called "uncountable infinities." The natural numbers are an example of a countably infinite set and the real numbers are supposed to be an example of an uncountably infinite set.
The postulate of a countably infinite set of integers is well accepted in set theory and number theory.
Agreed.
However, that does not imply the existence of an infinite integer. The set of integers has infinite cardinality, but each individual integer has finite magnitude.
And in which maths bible does it specify an integer can be obtained in this way only a *finite* number of times?
Virtually all of them. Here is a quick heuristic inductive proof of this fact for the natural numbers:
2 can be obtained by adding one to itself a finite number of times.
Suppose n can be obtained by adding one to itself a finite number of times.
Then, (n+1) can be obtained by adding one to itself a finite number of times, and then once more. Thus, (n+1) can be obtained by adding one to itself a finite number of times.
Therefore, by the Law of Mathematical Induction, if n is an integer such that n >= 2 then n can be obtained by adding 1 to itself a finite number of times.
(The Law of Mathematical Induction applies because it is part of the definition of the natural numbers)
I have done this already in Post #7 of this thread, using your own argument to show the absurdity of Cantor's method (if you like, a kind of reductio ad absurdum argument)
An argument is invalid if and only if one of its steps is invalid. So, if your analysis is correct, you should be able to find an invalid step.
Note that if your analysis is correct, and there does not exist an invalid step, you've proven that the axiomatic system you were using is inconsistent.
It is well established in set theory that each of the sets of natural numbers, integers and rational numbers is countably infinite.
This means that each of these sets has infinite cardinality.
This means that there are infinitely many natural numbers, integers and rational numbers.
Any natural number or integer which is infinite must have an infinite number of digits.
As I mentioned above, the fact the set of natural numbers is infinite does not imply that there is a natural number that is infinite.
Since this is an infinite set of integers then the largest member of this set must be infinite
Why do you think there is a largest member? Here's a proof otherwise:
Suppose M is the largest integer.
M + 1 is an integer.
0 < 1
M + 0 < M + 1
M < M + 1
Thus there exists an integer larger than M. This contradicts the assumption that M is the largest integer.
Therefore, there does not exist a largest integer.
Let the largest possible natural number be Z. According to you, Z is finite. However, in that case card(Z) = Z (a finite number) and not aleph0 (infinity)
According to us, card(Z) is not a natural number. It is a cardinal number. In fact, card(S) is a cardinal number for any set S, whether finite or infinite.
It is true, though, that the finite cardinals form a model of the natural numbers.