Any help today would be appreciated, thanks.

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In summary, the rational roots of P(x) = 2x^4-5x^3+5x^2-5x+3 are 1 and 3/2, which can be found using the rational root theorem. This theorem states that any rational root of a polynomial must be of the form m/n, where m is a factor of the leading coefficient and n is a factor of the constant term. In this case, the leading coefficient is 2 and the constant term is 3, which are both prime numbers, making the possible rational roots limited.
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Homework Statement


wtihout using a graphing calc, find the rational roots of P(x) = 2x^4-5x^3+5x^2-5x+3



Homework Equations





The Attempt at a Solution



The answers are 1 and 3/2, because this is a homework question. I don't know how they got that though. If anybody can help me today that would be appreciated.

Thanks,
~Link2110
 
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Hint: Look up the "rational root theorem":wink:
 
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If that isn't clear (thanks, Dick) the rational root theorem says that any rational root of [itex]a_ix^i+ a_{i-1}x^{i-1}+ \cdot\cdot\cdot+ a_1x+ a_0[/itex] must be of the form m/n where m divided [itex]a_i[/itex] and n divides [itex]a_0[/itex] (that's because if x= m/n is root then (x- m/n)= (1/n)(nx- m) must be a factor). Here, [itex]a_n= a_4= 2[/itex] and [itex]a_0= 3[/itex]. Since those are prime, there are not a whole lot of possiblities.
 

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