- #1
HelgaMan
- 5
- 0
I was reading a lab online and I came across one that dealt with Specific Gravity and Buoyany and stuff.. and then they had these equations:
*Note: p = density, M = mass, V = Volume, g = gravitational acceleration, W = Weight
Subscripts: S = substance, W = water
SG = pS / sW = (MS / VS) / (MW / VW) = (MSg / VS) / (MWg / VW) = (WS / VS) / (WW / VW)
and
SG = (WS / V) / (WW / V) = WS / WW = WS / (buoyant force) = WS / (loss of weight in water)
= WS / (WS - weight of substance in water)
which all makes sense to me, mathmatically.. but then i thought about this part "WS / (buoyant force)" and that kinda throws me off because isn't Archimede's Principle that weight of an object is equal to the buoyant force.. and that makes SG always 1? but I am pretty sure that's not the case, though..
well, idk, I am sure all you smart people will see something that i dont, lol.![Stick Out Tongue :-p :-p](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
*Note: p = density, M = mass, V = Volume, g = gravitational acceleration, W = Weight
Subscripts: S = substance, W = water
SG = pS / sW = (MS / VS) / (MW / VW) = (MSg / VS) / (MWg / VW) = (WS / VS) / (WW / VW)
and
SG = (WS / V) / (WW / V) = WS / WW = WS / (buoyant force) = WS / (loss of weight in water)
= WS / (WS - weight of substance in water)
which all makes sense to me, mathmatically.. but then i thought about this part "WS / (buoyant force)" and that kinda throws me off because isn't Archimede's Principle that weight of an object is equal to the buoyant force.. and that makes SG always 1? but I am pretty sure that's not the case, though..
well, idk, I am sure all you smart people will see something that i dont, lol.