- #1
zetafunction
- 391
- 0
let be A , B and C three non-commuting observables
my question is how can one solve the problem with associative property ? i mean
[tex] (AxB)xC [/tex] will in general be different from [tex] Ax(BxC) [/tex]
and if we had 4 A, B ,C ,D instead of three the problem is even worse , how can anyone deal with it ?? i mean since the observable do not commute and we can not apply the associative property is there any ambiguity in QM ?? or similar ??
my question is how can one solve the problem with associative property ? i mean
[tex] (AxB)xC [/tex] will in general be different from [tex] Ax(BxC) [/tex]
and if we had 4 A, B ,C ,D instead of three the problem is even worse , how can anyone deal with it ?? i mean since the observable do not commute and we can not apply the associative property is there any ambiguity in QM ?? or similar ??