- #1
Huskies213
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First is this correct?
The pH of a 150 mL aqueous solution of 2.13 x10^-3 M HCl is
pH = -Log (2.13 x10^-3)
pH = 2.672
and how would you solve this one?
A .1M aqueous solution of an acid HA has a pH of 4.0 what is the pKa of HA?
The pH of a 150 mL aqueous solution of 2.13 x10^-3 M HCl is
pH = -Log (2.13 x10^-3)
pH = 2.672
and how would you solve this one?
A .1M aqueous solution of an acid HA has a pH of 4.0 what is the pKa of HA?