Calculating Electric Fields Using Coulomb's Law

In summary, use Coulomb's law to find the magnitude and direction of the electric field at points A and B in Fig. 16-57 due to two positive charges (Q = 4.0 µC). Apply the law separately for each charge and use vector superposition to find the resultant components. Resolve the electric field into its x and y components using cosine and sine.
  • #1
AbbyGirl
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0

Homework Statement



Use Coulomb's law to determine the magnitude and direction of the electric field at points A and B in Fig. 16-57 due to the two positive charges (Q = 4.0 µC) shown.

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The Attempt at a Solution



Basically, I'm completely lost. I've applied Coulomb's law to find the magnitudes of the contributing electric fields.

Can anyone help me solve this problem/ at least get started. Thanks so much, god bless.
 
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  • #2
Apply Coulomb's law for each charge separately.
Then use vector superposition once you find electric field for each charge.
 
  • #3
An electric field is a vector so it has a magnitude and a direction. Using Coulomb's Law gives an expression for E:

[tex]\vec{E}=\frac{\vec{F}}{q}\mbox{ where q is a test charge}[/tex]

[tex]\vec{F}=\frac{qQ\hat{r}}{4\pi \varepsilon_0 \ r^2}[/tex]

[tex]\mbox{where }\hat{r}\mbox{ is the unit vector in the r direction}[/tex]

So,

[tex]\vec{E}=\frac{Q\hat{r}}{4\pi \varepsilon_0 \ r^2}[/tex]

where r is the distance from the charge to the point in question. Resolve E into Ex and Ey using cosine and sine. Then add these resolved components to find the resultant components.
 

FAQ: Calculating Electric Fields Using Coulomb's Law

What is an electric field in 2 dimensions?

An electric field in 2 dimensions is a vector field that describes the strength and direction of the electric force at any given point in a 2-dimensional space. It is represented by arrows pointing in the direction of the force and the length of the arrow represents the strength of the force.

How is an electric field in 2 dimensions calculated?

An electric field in 2 dimensions is calculated using the equation E = F/q, where E is the electric field strength, F is the electric force, and q is the charge. In 2 dimensions, the electric field is calculated for both the x and y directions separately.

What is the difference between an electric field in 2 dimensions and 3 dimensions?

The main difference between an electric field in 2 dimensions and 3 dimensions is the number of dimensions in which the field is calculated. In 2 dimensions, the electric field is calculated for the x and y directions, while in 3 dimensions, it is calculated for the x, y, and z directions. This means that the electric field in 3 dimensions is more complex and can vary in all three dimensions, while in 2 dimensions it is simpler and only varies in two dimensions.

What is the significance of electric fields in 2 dimensions?

Electric fields in 2 dimensions are significant because they help us understand the behavior of electric charges in a 2-dimensional space. They are also used in many practical applications, such as designing electronic circuits and analyzing the behavior of charged particles in 2-dimensional systems.

Can an electric field in 2 dimensions exist without a charge?

No, an electric field in 2 dimensions cannot exist without a charge. The presence of a charge is necessary for an electric field to form, as the charge creates the force that produces the electric field. Without a charge, there would be no force and therefore no electric field.

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