Calculating Normalization Factor for 1s Atomic Orbital of H

In summary, Geronimo was asked to show that the Normalization factor for the 1s atomic orbital of H is 1/(\xi a_o^3)^\frac{1}{2}. He was given d \Tau = r^2 sin \Theta; dr d\Theta d\Phi and \int_{0}^{\infty}x^n e^{ax} dx=n!/a^n+1. He was advised to change variables in the theta and phi integrals to x=\cos(\theta) and then it becomes a lot nicer. He was also advised to solve for N. He managed to do so by imposing \int_0
  • #1
geronimo123
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Hi all! I hope somebody is able to help me on my way with this question.

I have been asked to show that the Normalization factor for the 1s atomic orbital of H is [tex]1/(\Pi a_o^3)^\frac{1}{2}[/tex]. The wavefunction is [tex]\psi(r) = N exp(-r / a_o)[/tex]

I'm given [tex]dt = r^2 sin \Theta[/tex] and [tex]dr d\Theta d\Phi[/tex] and [tex]\int_{0}^{\infty}x^n e^{ax} dx=n!/a^n+1[/tex]

I must admit I'm clueless which direction to go. It was mentioned to me, that squaring the wavefunction is the first step, but I cannot arrive at the given constant. Am I starting off on the wrong foot?

Thanks for any input, in advance.

geronimo
 
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  • #2
geronimo123 said:
Hi all! I hope somebody is able to help me on my way with this question.

I have been asked to show that the Normalization factor for the 1s atomic orbital of H is [tex]1/(\xi a_o^3)^\frac{1}{2}[/tex]. The wavefunction is [tex]\psi(r) = N exp(-r / a_o)[/tex]

I'm given [tex]d \Tau = r^2 sin \Theta[tex];[tex]dr d\Theta d\Phi[/tex] and [tex]\int_{0}^{\infty}x^n\e^-ax\dx=n!/a^n+1[/tex]

I must admit I'm clueless which direction to go. It was mentioned to me, that squaring the wavefunction is the first step, but I cannot arrive at the given constant. Am I starting off on the wrong foot?

Thanks for any input, in advance.

geronimo
You have all the pieces in place.
Just impose [itex] \int_0^\infty dr r^2 \int_0^{2 \pi} d\phi \int_0^\pi sin(\theta) d\theta \,\,N^2 e^{-2 r /a_0} =1 [/itex] and solve for N.
 
  • #3
I must admit that my integration is not what it used to be. I'm taking some physical chemistry night classes where this problem was set. How might one initially solve for N?
 
  • #4
geronimo123 said:
I must admit that my integration is not what it used to be. I'm taking some physical chemistry night classes where this problem was set. How might one initially solve for N?

The [tex]\phi[/tex] integral just adds a factor of [tex]2\pi[/tex], change variables in the [tex]\theta[/tex] integral to [tex]x=\cos(\theta)[/tex] and then it becomes a lot nicer.

Good luck.
Eoin Kerrane.
 
  • #5
geronimo123 said:
I must admit that my integration is not what it used to be. I'm taking some physical chemistry night classes where this problem was set. How might one initially solve for N?
the theta integral gives 2. The phi integral gives 2 pi. For the r integral, you have a formula. just compare the r integral to the formual you have, term by term (what is n? etc) and you will have the result of the r integration. Then you have N^2 times an expression = 1 and you solve for N
 
  • #6
Super guys, I have managed it finally thanks to your help. Best regards
 

FAQ: Calculating Normalization Factor for 1s Atomic Orbital of H

How do you calculate the normalization factor for the 1s atomic orbital of hydrogen?

The normalization factor for the 1s atomic orbital of hydrogen can be calculated using the formula:

N = (3/4πa3)1/2
where a is the Bohr radius (a0) equal to 0.529 Å.

What is the significance of the normalization factor in calculating the 1s atomic orbital of hydrogen?

The normalization factor ensures that the wavefunction for the 1s atomic orbital of hydrogen is properly normalized, meaning that the total probability of finding the electron in the orbital is equal to 1. It is a necessary step in accurately describing the behavior of electrons in the hydrogen atom.

Can the normalization factor for the 1s atomic orbital of hydrogen be calculated using experimental data?

No, the normalization factor must be calculated using theoretical methods based on the properties and behavior of electrons in the hydrogen atom. It cannot be determined solely through experimental data.

How does the normalization factor change for other atomic orbitals of hydrogen?

The normalization factor for other atomic orbitals of hydrogen can be calculated using the same formula, but with different values for a (the Bohr radius) and n (the principal quantum number). As n increases, the normalization factor will decrease, meaning that the probability of finding the electron in the orbital becomes more spread out.

Can the normalization factor be used for other atoms besides hydrogen?

No, the normalization factor is specific to the hydrogen atom and cannot be used for other atoms. Each atom has its own unique wavefunction and normalization factor that must be calculated separately.

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