Calculating Pressure at Depth in Oceans/Lakes

In summary, if the lake is 20,000 feet deep and the pressure is 625 atmospheres, then it can hold a column of water 32 feet high.
  • #1
cragar
2,552
3
if I want to calculate the pressure at a given depth in the ocean or a lake
1 atmosphere of pressure will support a column of water 32 feet high right?
so if the lake is 20,000 feet deep can we just divide 20,000
by 32 and get 625 atmospheres at the depth?

i see that the pressure equation is p=(rho)gh is this measured in Pascal’s .
This is not a homework question.
 
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  • #2
Yes, but

P = rho g h

is an equation that is valid in any arbitrary system of units. The whole point of units is that you can choose whatever units are most convenient for you.
 
  • #3
The pressure under water [tex]P = \rho gh + P_{\text{atm}}[/tex] is measured in Pascal.
 
  • #4
fatra2 said:
The pressure under water [tex]P = \rho gh + P_{\text{atm}}[/tex] is measured in Pascal.

This equation is valid in any arbitrary units. If you were to take this equation and then substitute numerical values in it, like
g = 9.81 m/s^2, then it is still unit independent, because the meters and seconds in this equation will transform covariantly when changing to other units (e.g. to miles and weeks from meters and seconds).

Only if you were to substitute numerical values like g = 9.81 ommitting the meters/second^2, then the equaion becomes unit dependent, it will only be valid in SI units. You are then effectively putting meter = second = kilogram = 1, analogous to what we do in theoretical physics when we put hbar = c = G = 1.

The answer you get for P will then be a number and then the unit Pascal has to be inserted by hand, it doesn't come out of the equation itself. You can also say that since we have put meter = second = kilogram = 1, you can multiply by any arbitrary combination of meters, seconds and kilograms, but only one combination is dimensionally correct. So, the correct unit, Pascal, was set to 1. We can thus multiply by Pascal as that is equal to 1 without changing anything. But then the equation has become dimensionally correct again, and therefore this is the correct way to put back the units.
 

FAQ: Calculating Pressure at Depth in Oceans/Lakes

What is the formula for calculating pressure at depth in oceans/lakes?

The formula for calculating pressure at depth in oceans or lakes is: Pressure = Density x Gravity x Depth. This is known as the hydrostatic pressure formula, where density is typically measured in kg/m³, gravity is 9.8 m/s², and depth is measured in meters.

How does pressure change with increasing depth in oceans/lakes?

As depth increases in oceans or lakes, pressure also increases. This is due to the weight of the water above pushing down on the water below. For every 10 meters of depth, pressure increases by approximately 1 atmosphere (14.7 pounds per square inch).

What units are used to measure pressure at depth in oceans/lakes?

The most commonly used unit for pressure at depth in oceans or lakes is atmospheres (atm). Other units that may be used include pounds per square inch (psi), kilopascals (kPa), and bar (bar).

How does salinity affect pressure at depth in oceans/lakes?

Salinity, or the amount of salt in the water, can affect pressure at depth in oceans or lakes. Water with a higher salinity will have a higher density, and therefore, higher pressure at a given depth compared to water with a lower salinity.

Can pressure at depth in oceans/lakes be calculated using only the depth measurement?

No, pressure at depth in oceans or lakes cannot be calculated using only the depth measurement. The density of the water and the acceleration due to gravity must also be taken into account in order to accurately calculate pressure.

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