Calculating Velocity in Circular Motion

In summary, the conversation discusses a physics problem involving energy conservation and the use of equations such as Ek=1/2mv2 and Ep=mgh. The question also involves circular motion and potential energy. The participants discuss the importance of velocity in the problem and how it can help determine the work done and changes in energy. They also consider the difference in height of the object after breaking the pencil and how it relates to changes in energy.
  • #1
mccarthyp64
5
0
1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.
 

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  • #2
mccarthyp64 said:
1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.

The question concerns energy and energy conservation. What forms of energy can you identify in the scenario?
 
  • #3
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.
 
  • #4
mccarthyp64 said:
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.

Why do you need velocity? What will velocity tell you?

Why do you suppose that the height of the object only reaches 0.14 m after it breaks the pencil rather than returning to its starting height of 0.30 m? What has changed?
 
  • #5
for q 25 velocity is the answer
and in 26 I need the work done
 
  • #6
mccarthyp64 said:
for q 25 velocity is the answer
and in 26 I need the work done

Both questions involve changes in energy. Consider the energy changes taking place.
 
  • #7
Ep=mgh=Ek=1/2mv2
1.176=0.4*9.8*0.3=1.176=0.5(0.4)(v)2
(1.176/0.5)/0.4=v2=5.88
√(5.88)=2.42=ANS!
YAY thanks gneill :)
 

FAQ: Calculating Velocity in Circular Motion

What is the formula for calculating the velocity in a circular path?

The formula for calculating velocity in a circular path is v = 2πr/T, where v is velocity, r is the radius of the circle, and T is the time taken to complete one full revolution.

How does velocity change in a circular path?

In a circular path, the velocity is constantly changing because the direction of motion is constantly changing. However, the speed remains constant as long as the radius and time period of the circular path remain constant.

How is the direction of velocity defined in a circular path?

The direction of velocity in a circular path is always tangent to the circle at a given point. This means that it is perpendicular to the radius at that point and points towards the center of the circle.

Can the velocity in a circular path be negative?

Yes, the velocity in a circular path can be negative. This happens when the object is moving in a clockwise direction, as opposed to the usual counterclockwise direction. The magnitude of the velocity remains the same, but the direction is opposite.

How does the velocity in a circular path affect the centripetal acceleration?

The velocity in a circular path is directly proportional to the centripetal acceleration. This means that as the velocity increases, the centripetal acceleration also increases. If the velocity is doubled, the centripetal acceleration will also double.

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