- #386
disregardthat
Science Advisor
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- 34
It's not possible. The equations are 10x+1/5 y + 5/4 z = 100, and z+y+z = 100, which gives 7(28x+3z) = 1600 by substituting y from the last equation into the first. 1600 is not divisible by 7, but 28z + 3z is an integer.