Can Linear Algebra Prove Vector Dependencies and Transformations?

Now consider the matrix whose columns are the five vectors in R4. This matrix is a 4x5 matrix, and since there are more columns than rows, there must be a nontrivial linear combination of the columns that gives the zero vector. This linear combination corresponds to the real numbers c1, ..., c5 in R4, and by setting c4=0 and c5=-c1-c2-c3, we have that c1x1+c2x2+c3x3=0 and c1+c2+c3+c4+c5=0, as desired.For question 2)Assume that x1, x2, x3 are linearly dependent. This means that there are real numbers
  • #1
mafquestion
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1) prove that for any five vectors (x1, ..., x5) in R3 there exist real numbers (c1, ..., c5), not all zero, so that BOTH

c1x1+c2x2+c3x3+c4x4+c5x5=0 AND c1+c2+c3+c4+c5=0

2)Let T:R5-->R5 be a linear transformation and x1, x2 & x3 be three non-zero vectors in R5 so that
T(x1)=x1
T(x2)=x1+x2
T(x3)=x2+x3

prove that {x1, x2, x3} are three linearly independent vectors.

any help would be greatly appreciated, thank you!
 
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  • #2
I've thought up a proof for the first one but it might be too complicated. I'll try to think of a simpler one if somebody else doesn't.

As for the second, assume that you have a linear combination of the three equal to zero. Map it under the matrix and see if something cool happens. Then see if it happens again. There's probably a contradiction with the assumptions in there somewhere ;)
 
  • #3
For question 1)

Extend a vector in R3 to one in R4 by adding a 1 in the fourth entry.
 
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FAQ: Can Linear Algebra Prove Vector Dependencies and Transformations?

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