- #1
rock_pepper_scissors
- 13
- 0
I am looking for a way to simplify the following expression:
##\sum\limits_{n=1}^{N}\ \sum\limits_{k=0}^{N-1}\ \sum\limits_{k'=0}^{N-1}\ \tilde{p}_{k}\ \tilde{p}_{k'}\ e^{2\pi in(k+k')/N}##.
I presume that the sum of the exponentials over ##n## somehow reduce to a Kronecker delta.
Am I wrong?
##\sum\limits_{n=1}^{N}\ \sum\limits_{k=0}^{N-1}\ \sum\limits_{k'=0}^{N-1}\ \tilde{p}_{k}\ \tilde{p}_{k'}\ e^{2\pi in(k+k')/N}##.
I presume that the sum of the exponentials over ##n## somehow reduce to a Kronecker delta.
Am I wrong?