- #1
brittydagal
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Homework Statement
The switch in the RC circuit shown in the figure is closed at t=0.
What is the charge on the capacitor at the time t = .35 ms?
I'm 95% sure I'm using the right formula but it's not working so I was wondering if I was possibly confusing something?
Homework Equations
q(t)= CV(1-e^(-t/RC))
The Attempt at a Solution
q(t)= CV(1-e^(-t/RC))
= (62*10^-6)(15 V)(1 - e^(-.00035/(10.8*(62*10^-6)))
= 3.78*10^-4 C ----> this is definitely wrong because the answer is asked for in mC -> any ideas?