- #1
rancam
- 23
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Hi .I'm a beginner at thermodynamics,very limited in my understanding of math.I have a handbook on CO2 properties.According to it the properties for CO2 at 47.3 bar are T=12C,H= -3792,S= -42.6,and for 34.85 bar,
T= 0 C,H= -3339.8,S=-39.33.If the gas expands from 47.3 to 34.85 bar,the gas will liquify because the enthalpy at the pressure of 47.3 is less than that for 34.85 bar.Can you please answer the following question
Will the temperature be 0 C,or will the liquification cause the temperature to fall below 0 C?If so,to determine the temperature would you simply divide the difference between the enthalpies by the heat capacity and subtract the quotient from 0 C (-3339.8 - -3792 =452.2 / 90 = 5.2 C. 0 - 5.2 = -5.2 C.According to the handbook the entropy for CO2 at this temperature (-5.2 C)and pressure (34.85 bar)is -74.64,considerably lower than at the vapor temperature.
T= 0 C,H= -3339.8,S=-39.33.If the gas expands from 47.3 to 34.85 bar,the gas will liquify because the enthalpy at the pressure of 47.3 is less than that for 34.85 bar.Can you please answer the following question
Will the temperature be 0 C,or will the liquification cause the temperature to fall below 0 C?If so,to determine the temperature would you simply divide the difference between the enthalpies by the heat capacity and subtract the quotient from 0 C (-3339.8 - -3792 =452.2 / 90 = 5.2 C. 0 - 5.2 = -5.2 C.According to the handbook the entropy for CO2 at this temperature (-5.2 C)and pressure (34.85 bar)is -74.64,considerably lower than at the vapor temperature.