Conditions Needed for Interchange of Double Limits

In summary, for the equation \lim_{x \to a} \lim_{y \to b} f(x,y)=\lim_{y \to b} \lim_{x \to a} f(x,y) to hold, f must be continuous at the point (a,b) as a function of two variables. This means that for any given small e, there exists a small d such that the difference between f evaluated at the point (a,b) and any other point within a distance of d from (a,b) is less than e. This condition ensures that the order of taking the limits of x and y does not affect the overall limit. In the example given, f(x,y)=x^y is not
  • #1
disregardthat
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What conditions must f satisfy if

[tex]\lim_{x \to a} \lim_{y \to b} f(x,y)=\lim_{y \to b} \lim_{x \to a} f(x,y)[/tex]

where [tex]\lim_{x \to a} f(x,y)[/tex] and [tex]\lim_{y \to b} f(x,y)[/tex] exists and are finite?
 
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  • #2
No one?
 
  • #3
Without condition you're statement is not true, consider
[tex] \frac{y^2}{x^2+y^2}. [/tex]
 
  • #4
Jarle said:
What conditions must f satisfy if

[tex]\lim_{x \to a} \lim_{y \to b} f(x,y)=\lim_{y \to b} \lim_{x \to a} f(x,y)[/tex]

where [tex]\lim_{x \to a} f(x,y)[/tex] and [tex]\lim_{y \to b} f(x,y)[/tex] exists and are finite?

Good question. I'm fairly sure that continuity in both x and y would be a sufficient condition.
 
  • #5
f should be continuous at (a,b) ... that is, continuous as a function of two variables. Continuous separately in each of x and y is not enough.
 
  • #6
g_edgar said:
f should be continuous at (a,b) ... that is, continuous as a function of two variables. Continuous separately in each of x and y is not enough.

Arh yes, thanks for the clarification g_edgar. :)

BTW, what is the simplist definition of continuity in this case. I was thinking of something like :

[itex] \exists \, \, \epsilon > 0 \, : \, |f(x+dx,y+dy) \, - \, f(x,y) | \leq \, k \, ||(dx,dy)|| [/tex] whenever [itex] ||(dx,dy)|| \leq \epsilon [/itex].

Is that basically correct?
 
  • #7
If [tex] f [/tex] is continuous the we certainly have [tex] \lim_{x\rightarrow a} \lim_{y\rightarrow b} f(x,y) = \lim_{y\rightarrow b} \lim_{x\rightarrow a} f(x,y). [/tex]
But you do not need that much. Consider
[tex] g(x,y) = \frac{xy}{x^2+y^2}. [/tex]
The function is discontinuous at [tex](0,0)[/tex], since [tex] \lim_{t\rightarrow 0} g(t,t) = 1/2 \neq 0 = \lim_{t\rightarrow 0} g(t,0) [/tex].
But we have [tex] \lim_{x\rightarrow 0} \lim_{y\rightarrow 0} g(x,y) = \lim_{y\rightarrow 0} \lim_{x\rightarrow 0} g(x,y)=0, [/tex] and [tex]\lim_{x\rightarrow 0} g(x,y) = 0 = \lim_{y\rightarrow 0} g(x,y)[/tex] exist and are finite.
 
  • #8
uart said:
Arh yes, thanks for the clarification g_edgar. :)

BTW, what is the simplist definition of continuity in this case. I was thinking of something like :

[itex] \exists \, \, \epsilon > 0 \, : \, |f(x+dx,y+dy) \, - \, f(x,y) | \leq \, k \, ||(dx,dy)|| [/tex] whenever [itex] ||(dx,dy)|| \leq \epsilon [/itex].

Is that basically correct?

No that's not it. Try again!
 
  • #9
Thanks for the replies.

Now, consider [tex]f(x,y)=x^y[/tex] on [tex](0,\infty)[/tex] in both variables. Is the function is continuous in both variables on the interval, and not only seperately? We have existing limits as [tex]x[/tex] and [tex]y \to 0[/tex] independently. They are 0 and 1 respectively. However, the resulting limit depends on the order of the limit composition.

How do you account for this example? What conditions do f fail to satisfy? And what is the difference between continuity in two variables, and continuity in two variables seperately?
 
  • #10
Jarle said:
Thanks for the replies.

Now, consider [tex]f(x,y)=x^y[/tex] on [tex](0,\infty)[/tex] in both variables. Is the function is continuous in both variables on the interval, and not only seperately?

Yes, [itex]f[/itex] is continuous on the whole product set [itex](0,\infty) \times (0,\infty)[/itex].

We have existing limits as [tex]x[/tex] and [tex]y \to 0[/tex] independently. They are 0 and 1 respectively. However, the resulting limit depends on the order of the limit composition.

How do you account for this example? What conditions do f fail to satisfy? And what is the difference between continuity in two variables, and continuity in two variables seperately?

The condition that fails: [itex]f[/itex] is not continuous at the point [itex](0,0)[/itex]

Remember what I said back there? "f should be continuous at (a,b)" ?
 
  • #11
How is continuity defined in a point for a function of 2 or more variables?
 
  • #12
A function f is continuous at a point v, if for every e>0 there is a d>0 such that
||f(v + u) - f(v)|| < e whenever ||u|| < d.
 

FAQ: Conditions Needed for Interchange of Double Limits

What are the conditions needed for interchange of double limits?

The conditions needed for interchange of double limits are:

  1. The existence of the double limit, meaning that both the inner and outer limits must exist.
  2. The uniform convergence of the inner limit, meaning that the inner limit must converge for all values of the outer variable.
  3. The continuity of the function, meaning that the function must be continuous at the point of interest.
  4. The convergence of the outer limit, meaning that the outer limit must converge as the variable approaches the point of interest.
  5. The independence of the order of integration, meaning that the order in which the limits are taken does not affect the final result.

Why is the existence of the double limit necessary for interchange of double limits?

The existence of the double limit is necessary for interchange of double limits because without it, the order in which the limits are taken can affect the final result. If the double limit does not exist, then the interchange of limits may not be possible.

What does uniform convergence of the inner limit mean?

Uniform convergence of the inner limit means that the inner limit must converge for all values of the outer variable. This ensures that the inner limit does not depend on the order in which the limits are taken, allowing for interchange of limits to be possible.

Why is the continuity of the function important for interchange of double limits?

The continuity of the function is important for interchange of double limits because it ensures that the function behaves predictably at the point of interest. If the function is not continuous at the point of interest, then the interchange of limits may not be valid, as the function's behavior may change as the limits are interchanged.

Can the order of integration affect the final result when interchanging double limits?

No, the order of integration should not affect the final result when interchanging double limits. This is known as the independence of the order of integration, and it is one of the conditions needed for interchange of double limits. If the function satisfies this condition, then the order in which the limits are taken should not affect the final result.

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