Conduction through cylinder wall

In summary: Integrate both sides to get T(r) = C1*ln(r) + C2 where C1 and C2 are constants. This is the temperature profile through the cylinder wall.
  • #1
RTW69
374
1

Homework Statement


I am trying to find the temperature profile through a cylinder wall. It is a one dimensional, steady state conduction problem without internal heat generation


Homework Equations


d/dr(r*dT/dr)=0 where r is radius and T is temperature


The Attempt at a Solution


I can find the solution easy enough if I assume internal heat generation
d/dr(r*dT/dr)=-r*q_gen/k I can separate variables and let the q_gen term equal 0 since there is no q_gen to get T(r)=c_1*ln(r)+c_2 I know the boundary conditions so the solution is pretty straight forward. What I would like to do is solve d/dr(r*dT/dr)=0 directly. I can take the derivative of r*dT/dr with respect to r and get d^2T/dr^2+1/r*dT/dr=0 I know I must integrate twice but my calculus is pretty much limited to separation of variables. I am nor sure how to integrate this equation. Any suggestions?
 
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  • #2
RTW69 said:

Homework Statement


I am trying to find the temperature profile through a cylinder wall. It is a one dimensional, steady state conduction problem without internal heat generation


Homework Equations


d/dr(r*dT/dr)=0 where r is radius and T is temperature


The Attempt at a Solution


I can find the solution easy enough if I assume internal heat generation
d/dr(r*dT/dr)=-r*q_gen/k I can separate variables and let the q_gen term equal 0 since there is no q_gen to get T(r)=c_1*ln(r)+c_2 I know the boundary conditions so the solution is pretty straight forward. What I would like to do is solve d/dr(r*dT/dr)=0 directly. I can take the derivative of r*dT/dr with respect to r and get d^2T/dr^2+1/r*dT/dr=0 I know I must integrate twice but my calculus is pretty much limited to separation of variables. I am nor sure how to integrate this equation. Any suggestions?

If d/dr(r*dT/dr)= 0 then r*dT/dr = C (a constant)

So dT/dr = C/r ...
 

FAQ: Conduction through cylinder wall

What is conduction?

Conduction is the transfer of heat or electricity through a material without any movement of the material itself.

How does heat transfer through a cylinder wall?

Heat can transfer through a cylinder wall through conduction, where heat energy is transferred from molecule to molecule within the material.

What factors affect conduction through a cylinder wall?

The factors that affect conduction through a cylinder wall include the material of the wall, its thickness, the temperature difference between the two sides of the wall, and the surface area of the wall.

What is the equation for calculating conduction through a cylinder wall?

The equation for calculating conduction through a cylinder wall is Q = (kAΔT)/d, where Q is the rate of heat transfer, k is the thermal conductivity of the material, A is the surface area of the wall, ΔT is the temperature difference between the two sides of the wall, and d is the thickness of the wall.

How can conduction through a cylinder wall be improved?

Conduction through a cylinder wall can be improved by using materials with higher thermal conductivity, increasing the surface area of the wall, and reducing the thickness of the wall. Additionally, using insulation can also help to reduce heat transfer through a cylinder wall.

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