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stonecoldgen
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Homework Statement
a 120g arrow moving at 75m/s strikes and sticks in a 3.63kg wooden block, initially at rest. If the coefficient of friction between the block and the table it sists on is 0.409, how far does the block slide before stopping?
Homework Equations
m1v1+v1+m2v2=m1v1'+m2v2'
fr=mu(coefficient of friction)mg=sigmaF+fr
maybe:
v'=v+2ad
The Attempt at a Solution
I substituted values for the conservation of momentum equation
m1v1+v1+m2v2=m1v1'+m2v2'
(.12)(75)+(3.63)(0)=(.12)v1'+(3.63)v2'
9=3.75v' (v1' and v2' are the same as they are now ''the same piece'')
v'=9/3.75
=2.4m/s
so i figured out how fast the arrow stuck on the block would go
now, i would calculate the friction force i guess (.409)(3.63)(9.8)=14.5N
but i have no time, therefore no acceleration and don't know what to do