- #1
wirefree
- 108
- 21
G’day.
I am here to clear my doubt about the dB scale, in general, and it’s use in calculating received power in a microwave cavity.
Given that I have arrived at received power (Pr in Watts) for a given input power (Pt), I understand that
10*log (Pt/Pr)
yields Pr in dB.
Now, say, the cavity’s a Directonal Coupler, which has an Insertion Loss (Il) of 0.5 dB. If I substract Il from Pr (in dB), and obtain a negaive number, that would violate basic principles as it implies Pr > Pt since log10 of a number less than 1 is negative.
Please do correct me.
Best Wishes for the Festive Season,
with kind regards,
wirefree
I am here to clear my doubt about the dB scale, in general, and it’s use in calculating received power in a microwave cavity.
Given that I have arrived at received power (Pr in Watts) for a given input power (Pt), I understand that
10*log (Pt/Pr)
yields Pr in dB.
Now, say, the cavity’s a Directonal Coupler, which has an Insertion Loss (Il) of 0.5 dB. If I substract Il from Pr (in dB), and obtain a negaive number, that would violate basic principles as it implies Pr > Pt since log10 of a number less than 1 is negative.
Please do correct me.
Best Wishes for the Festive Season,
with kind regards,
wirefree