Degree of a Map: Finding Antipodal Points for Odd Degree Functions

In summary, the students are discussing two questions: 1) How to show that deg(f(g(x)) = deg(f)*deg(g) and 2) How to prove the existence of a pair of antipodal points that are mapped to antipodal points when the degree of f is odd. In the first question, the students have tried counting preimages but realize that it does not take into account the sign of the derivative at each preimage. In the second question, they are unsure how to start and are considering different ideas, such as using a fixed point theorem or studying a function that measures the difference between f(x) and f(-x). The students also note that odd degree is a necessary condition.
  • #1
kbfrob

Homework Statement


Two questions: 1) Show that deg(f(g(x)) = deg(f)*deg(g)
2) f: Sn -> Sn
deg(f) is odd
then show there exists a pair of antipodal points that are mapped to antipodal points



The Attempt at a Solution


1) I have tried the method of just counting preimages, but i don't think this is the right direction. i know intuitively the deg of map between spheres is how many times you "wrap" the sphere around, and what i trying to show supports this, but i don't know how to show it rigorously.

2) We are dealing with antipodal maps in class, so i am trying to use them, but i have no idea how to use the fact that the degree of f is odd. i don't recall there being any fundamental difference between a map of odd and even degree.
 
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  • #2
kbfrob said:
1) I have tried the method of just counting preimages, but i don't think this is the right direction.
What doesn't work about it?
 
  • #3
it doesn't take into account the sign of the dervative at each of the preimages. in other words, the degree is not just the number of preimages. I'm not sure how to reconcile this.
 
  • #4
kbfrob said:
it doesn't take into account the sign of the dervative at each of the preimages. in other words, the degree is not just the number of preimages. I'm not sure how to reconcile this.
Well, what if you count preimages together with their sign? Or modify the maps so that they have positive derivative at each preimage?
 
  • #5
alright i got it. thank you very much.

any ideas on the second question?
i don't even know how to start.
 
  • #6
kbfrob said:
alright i got it. thank you very much.

any ideas on the second question?
i don't even know how to start.
Nothing seems obvious to me. I suspect if I knew the content of the current chapter / previous couple chapters, something would leap out at me!

My best ideas at the moment are:
1. Try and apply some sort of fixed point theorem
2. Say something clever involving the quotient map Sn --> Sn / ~, where ~ is the relation that identifies antipodal points
3. Study some gadget that measures how different f(x) and f(-x) are from being antipodal (using -x to denote the point antipodal to x)

It's easy to see that odd degree is a necessary condition -- consider the standard maps [itex]f(\theta) = k \theta[/itex] of degree k on the circle.
 
  • #7
If f is a function of odd degree, mapping Sn to Sn, A(p) be the function that maps each point to its antipodal point and look at f(p)- f(A(p)).
 

FAQ: Degree of a Map: Finding Antipodal Points for Odd Degree Functions

What is the degree of a map?

The degree of a map is a mathematical concept used to describe the number of times a given point is mapped onto itself by a function. It is typically denoted by the symbol "d" and can be thought of as the "multiplicity" of a point in the mapping.

How is the degree of a map calculated?

The degree of a map can be calculated by using the Brouwer degree formula, which involves determining the winding number of a path around the point being mapped. Alternatively, it can also be calculated by finding the number of pre-images of a point and dividing by the number of points in the image space.

What are antipodal points?

Antipodal points are two points on opposite ends of a sphere or other curved surface that are the same distance from a given point, known as the center. They can also be thought of as "opposite" points on a globe.

Why is it important to find antipodal points for odd degree functions?

Finding antipodal points for odd degree functions is important because it allows us to determine the degree of the function by looking at only half of the sphere or curved surface. This can simplify calculations and make it easier to analyze the function.

How do you find antipodal points for odd degree functions?

To find antipodal points for odd degree functions, you can use the fact that odd degree functions will always have at least one antipodal pair of points. You can also use the formula x' = -x, y' = -y, z' = -z to find the antipodal point of a given point (x,y,z) on a sphere.

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