Derivation of Kepler's laws- differential equation question

In summary, the equation u" + u = km/L^2 has a solution of the form u(theta) = km/L^2 + C cos(theta - theta(o)). This is because a linear differential equation with a non-zero additional term has a solution that is a sum of a general solution and a particular solution. In this case, the general solution is u(theta) = C cos(theta - theta(o)), while the particular solution is u(theta) = km/L^2. Therefore, the general solution for the given equation is u(theta) = km/L^2 + C cos(theta - theta(o)).
  • #1
ddoctor
9
0
Hi group,

Could someone 'remind me' why the equation u" + u = km/L^2 has the solution of the form u(theta) = km/L^2 + C cos(theta - theta(o)).
Any references would be appreciated.
Thanks

Dave
 
Physics news on Phys.org
  • #2
a linear differential equation with non zero additional term has a soulution which is a sum of a general solution of this equation with zero additional term and a particular solution of this equation. To be more clear (I assume that theta is independent variable) the equation

[tex]u^{''}+u=0[/tex]
has solution
[tex]u_0=C\times cos(\theta-\theta_0)[/tex]

on the other hand, your equation has a particular solution

[tex]u_p=km/L^2=const[/tex]
so the general solution is

[tex]u=u_0+u_p[/tex]
 
  • #3


Hi Dave,

The equation u" + u = km/L^2 is known as the harmonic oscillator equation and it can be derived from Newton's second law for a body moving under the influence of a central force, such as the gravitational force. This equation is also known as the equation of motion for a simple harmonic oscillator.

To solve this differential equation, we can use the method of variation of parameters. This involves assuming a solution of the form u(theta) = A cos(theta) + B sin(theta), where A and B are constants to be determined. Substituting this into the equation, we get:

u" + u = -A cos(theta) - B sin(theta) + A cos(theta) + B sin(theta) = 0

This means that A and B must satisfy the equations A = km/L^2 and B = 0. Therefore, the solution to the differential equation is u(theta) = km/L^2 cos(theta) = km/L^2 + C cos(theta - theta(o)).

This solution is in the form of a superposition of a constant term and a cosine function, which represents the oscillatory behavior of the system. The constant term represents the equilibrium position of the system, while the cosine term represents the oscillations around this equilibrium position.

I hope this helps to clarify the solution to the differential equation. For further references, you can refer to any textbook on classical mechanics or celestial mechanics, which will provide a detailed derivation of Kepler's laws from the harmonic oscillator equation.

 

FAQ: Derivation of Kepler's laws- differential equation question

What is Kepler's first law?

Kepler's first law, also known as the law of ellipses, states that planets orbit the sun in elliptical paths with the sun at one focus.

What is the significance of Kepler's laws?

Kepler's laws describe the motion of planets around the sun, providing a fundamental understanding of the laws of planetary motion. They also paved the way for Isaac Newton's theory of gravity.

How is Kepler's second law mathematically expressed?

Kepler's second law, also known as the law of equal areas, is expressed as "a line joining a planet and the sun sweeps out equal areas in equal intervals of time." This can be mathematically represented as dA/dt = constant, where dA is the change in area and dt is the change in time.

What is the formula for Kepler's third law?

Kepler's third law, also known as the law of harmonies, states that the square of a planet's orbital period is directly proportional to the cube of its semi-major axis. The formula for this is T^2 = (4π^2/GM)*a^3, where T is the orbital period, G is the gravitational constant, M is the mass of the central body, and a is the semi-major axis.

How does differential calculus relate to Kepler's laws?

Differential calculus is used to derive Kepler's laws from Newton's law of gravitation. By setting up a differential equation for the motion of a planet around the sun, Kepler's laws can be derived and understood in terms of calculus and mathematical principles.

Back
Top