- #1
ybhathena
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Homework Statement
Sum starting from n=1 to infinity for the expression, (3/4^(n-2))
What the solutions manual has done is multiply the numerator and the denominator by 4.
12/(4^(n-1))
I don't know what they have done from here on:
12 / (1 - 1/4)
= 16
Can someone explain the solution? Thank you.