Difference in radius, same power and intensity?

In summary, the conversation discusses the calculation of acoustic power propagating through a spherical surface with different radii. The power is constant at 0.13 W, but the intensity decreases as the distance from the source increases. This concept is illustrated using the equation I = P/4∏r^2.
  • #1
SPcle
2
0

Homework Statement


How much acoustic power propagates through a spherical surface (sound source in centre) with radius equal to 1.0m? with radius equal to 5.0m?

I = 10^-2 W/m^2
r = 1.0m or 5.0m
f = 50kHz
t = 2.0*10^-3s
IL = 100dB

Homework Equations


I = P/4∏r^2


The Attempt at a Solution


i figured out that when r = 1.0, power must be 1.3*10^-1W. However, when I work out the intensity when r = 5.0, i get:

10^-2 = P/4*∏*25
(10^-2)(4*∏*25) = P
3.1W = P

However, the answer states that the power for both spheres is 0.12W... What concept am I not understanding?
 
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  • #2
It is the same sound source which produces I = 10^-2 W/m^2 at unit distance, so its power is 0.13 W. The same power propagates through any concentric spherical surface, with less and less intensity.

ehild
 
  • #3
ooh, i see. so basically the power stays the same because it's the same sound source (a bat, in this case), but the intensity becomes a lot less in distance. i understand now, thanks!
 
  • #4
SPcle said:
ooh, i see. so basically the power stays the same because it's the same sound source (a bat, in this case), but the intensity becomes a lot less in distance. i understand now, thanks!

You understood it quick:smile: You are welcome.

ehild
 
  • #5


The concept that you may be missing is that power and intensity are not solely dependent on the radius of the spherical surface. They are also affected by the frequency and time parameters provided in the problem. In order to accurately compare the power and intensity at each radius, you would need to use the equation I = P/4∏r^2 and solve for P using the given values for I, r, f, and t. This will result in the same power of 0.12W for both radii of 1.0m and 5.0m.
 

FAQ: Difference in radius, same power and intensity?

What is the relationship between radius, power, and intensity?

The relationship between radius, power, and intensity is that they are all related to each other through the inverse square law. This means that as the radius increases, the power and intensity decrease, and vice versa.

How does the difference in radius affect the power and intensity of a source?

A smaller radius will result in a higher power and intensity, while a larger radius will result in a lower power and intensity. This is because a smaller radius means the same amount of power is spread over a smaller area, resulting in a higher intensity.

Can two sources with the same power and intensity have different radii?

Yes, two sources can have the same power and intensity but different radii. This is because the power and intensity are determined by the amount of energy being emitted, while the radius is the distance from the source at which the intensity is being measured.

How does the difference in radius affect the distance at which the intensity is measured?

The difference in radius does not affect the distance at which the intensity is measured. The intensity is measured at a specific distance from the source, regardless of the source's radius. However, the intensity will vary depending on the source's radius due to the inverse square law.

Is the difference in radius more significant than the difference in power and intensity?

This depends on the context and the specific values being compared. In general, the difference in radius will have a greater impact on the intensity than the difference in power and intensity. However, if the difference in power and intensity is significant enough, it may outweigh the impact of the difference in radius.

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