Differentiaitng Problem (dy/dx)

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In summary, the conversation is about finding the rate of change of the y-component of a particle moving along the graph of the function y=x^2+2x, with the x-component changing at a constant rate of 1cm/sec. The formula for finding the rate of change is dy/dx=2x+2, and by plugging in the given values of x, the rate of change (dy/dt) can be calculated. The shape of the graph is important to consider, as the derivative represents the slope of the tangent line, and as x increases, the tangent line gets steeper, resulting in a faster rate of change for y.
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Cate
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Homework Statement


Questions: Imagine a particle along the graph of the function y=x^2+2X. The X-component of the particle changes at a constant rate of 1cm /sec. First, evalute how fast the y-component of the particle is changing at the various points below. Then for each, explain why your answer makes sense with the shape of the graph in mind.

This is what I did:

Know:

dx/dt= 1

x= -3,-2,-1,1


Find:

dy/dt= ?


y=2X+2 dy/dt= 2(-3)+2 dx/dt =-4

and so on for all four values of x am I right?


Thanks!
 
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  • #2
Um. I think so. y=x^2+2x. dy/dt=2x*dx/dt+2*dx/dt. Your notation is a little ambiguous.
 
  • #3
Cate said:

Homework Statement


Questions: Imagine a particle along the graph of the function y=x^2+2X. The X-component of the particle changes at a constant rate of 1cm /sec. First, evalute how fast the y-component of the particle is changing at the various points below. Then for each, explain why your answer makes sense with the shape of the graph in mind.

This is what I did:

Know:

dx/dt= 1

x= -3,-2,-1,1


Find:

dy/dt= ?


y=2X+2 dy/dt= 2(-3)+2 dx/dt =-4
You mean dy/dx= 2x+ 2 and then dy/dt= -4.

and so on for all four values of x am I right?


Thanks!
 
  • #4
Thanks guys, what about the seond half of the question? explain why your answer makes sense with the shape of the graph in mind.
 
  • #5
Remember that the derivative is the slope of the tangent line. What happens to the tangent line to the graph as x gets larger?
 
  • #6
tangent line gets steeper?
 
  • #7
Yes, and so how fast does y change compared with x?
 

FAQ: Differentiaitng Problem (dy/dx)

What is differentiation?

Differentiation is a mathematical process that involves finding the rate of change of a function with respect to its independent variable. It is commonly used in calculus to find the slope of a curve at a specific point.

Why is differentiation important?

Differentiation is important because it allows us to analyze and understand the behavior of a function. It helps us find the maximum and minimum values of a function, identify the concavity of a curve, and solve optimization problems. It also has numerous applications in fields such as physics, engineering, and economics.

How do you differentiate a function?

To differentiate a function, you need to use certain rules and formulas depending on the type of function. These rules include the power rule, product rule, quotient rule, and chain rule. The process involves finding the derivative of each term in the function and combining them using these rules.

What is the difference between dy/dx and d/dx?

The notation dy/dx represents the derivative of a function y with respect to its independent variable x. It is used to find the slope of a curve at a specific point. On the other hand, d/dx represents the differential operator, which is used to find the derivative of a function with respect to its independent variable. It is a more general notation that can be used to differentiate any type of function.

Can differentiation be applied to any type of function?

Yes, differentiation can be applied to any type of function, including polynomial, exponential, logarithmic, and trigonometric functions. However, the rules and formulas used for differentiation may vary depending on the type of function. For example, the power rule is used for polynomial functions, while the chain rule is used for composite functions.

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