Do Charged Particles Exhibit Stronger Gravitational Fields?

In summary, it is unknown whether a subatomic particle with an electric field has a greater gravitational field than one without.
  • #36
quantumfoam said:
Just to be clear, I can't add the stress-energy tensor of a charged subatomic particle in terms of its mass and the stress-energy tensor of the same subatomic particle in terms of its charge?
You can add the stress energy tensors, but the resulting curvature tensors don't add.
 
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  • #37
quantumfoam said:
Just to be clear, I can't add the stress-energy tensor of a charged subatomic particle in terms of its mass and the stress-energy tensor of the same subatomic particle in terms of its charge?

Hello

Including charge in the equations of motion opens the door to Lorentz force to be applied on the test particles. This happens to be the case if an electromagnetic stress tensor is added to the gravitational one since the Lorentz force is related with electromagnetic strength tensor [itex]F_{{\mu}{\nu}}[/itex] in GR, as many others may have informed you of. Since it is an additive effect, then of course the field would be slightly stronger though for a subatomic particle like electron, gravity loses to Coulomb strength by [itex]10^{-42}[/itex] which is quite decent for it to be neglected in any physical scale.

P
 
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