ELECTRIC field due to a solenoid, or a current-carrying wire, or

In summary, the conversation discusses the lack of discussion about electric fields produced by magnetic field geometries, such as solenoids, straight wires, and rings of current. The reason for this is due to Maxwell's equations, which state that with no changing magnetic field, the electric field has no curl (Faraday's law) and with no net charge, the electric field has no divergence (Gauss' law). This means that in the case of steady currents, the electric field is identically zero. However, in cases where there is a changing magnetic field or non-uniform conductivity, there may be a non-zero electric field present.
  • #1
AxiomOfChoice
533
1
We always talk about the magnetic field produced by solenoids, straight wires of current, and rings of current, etc., but why do we never talk about the ELECTRIC fields produced by these geometries? I mean, there are CHARGES, right? So there must be electric fields present, right? Or am I wrong?

I know a CHANGING magnetic field produces an electric field, but why don't STEADY currents produce electric fields?
 
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  • #2
This just follows directly from Maxwell's equations. With no changing B field the E field has no curl (Faraday's law), and with no net charge the E field has no divergence (Gauss' law). A field with no curl and no divergence is identically 0.
 
  • #3
Current-carrying wires contain equal amounts of positive and negative charge, and are electrically neutral.
 
  • #4
DaleSpam said:
. A field with no curl and no divergence is identically 0.

well, it may be constant in general. in case of wire with conductivity sigma, there is electric field inside the wire( given by ohm's law).. although if the current is steady and the conductivity uniform the divergence of the electric field becomes ZERO.
is the curl of electric field in this case also zero? i guess it should be because charge density in this case is constant with time everywhere.
 
  • #5


You are correct, there are electric fields present in these geometries due to the presence of charges. However, the reason we often focus on the magnetic field is because it is typically much stronger and more easily measurable in these situations. The strength of the electric field is directly proportional to the charge, whereas the strength of the magnetic field is proportional to the current. In most cases, the current is much larger than the charge, making the magnetic field more significant.

Additionally, the electric field produced by a steady current is typically small and uniform, whereas the magnetic field can vary greatly in strength and direction. This makes the electric field less noticeable and less commonly discussed in these situations.

However, it is important to note that both the electric and magnetic fields are present and play important roles in understanding the behavior of these geometries. In fact, the interplay between the two fields is what allows for phenomena such as electromagnetic induction, where a changing magnetic field can create an electric current.

Overall, while the electric field may not be as prominent in these situations, it is still an important factor to consider and is always present in conjunction with the magnetic field.
 

FAQ: ELECTRIC field due to a solenoid, or a current-carrying wire, or

What is an electric field?

An electric field is a physical field that surrounds and is created by electric charges. It exerts a force on other charged particles and can influence the behavior of those particles.

What is a solenoid?

A solenoid is a coil of wire that carries an electric current. It is often used to create a magnetic field and can also produce an electric field.

How is the electric field created by a solenoid?

The electric field created by a solenoid is produced by the movement of electric charges through the wire. As the charges move, they create a disturbance in the surrounding space, creating an electric field.

What is the direction of the electric field produced by a current-carrying wire?

The electric field produced by a current-carrying wire is always directed perpendicular to the wire, in a circular pattern around the wire.

How does the electric field change with distance from a current-carrying wire?

The strength of the electric field produced by a current-carrying wire decreases as the distance from the wire increases. This is because the electric charges are spread out over a larger area, resulting in a weaker field.

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