Electric Fields Question (deflection? :S? and more)

In summary, the conversation discusses the problem of an electron entering a parallel plate apparatus with given dimensions and velocity, and the goal of finding the vertical deflection and final velocity of the electron. The solution involves finding the time taken, electric field, force, and acceleration of the electron, and treating it as a projectile to solve for the desired values.
  • #1
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Homework Statement



An electron enters a parallel plate apparatus 10cm long and 2.0cm wide, moving horizontally at 8.0 x 10^7 m/s.

If the potential difference acrros the plates is 600V:

a) the vertical deflection of the electron from its original path.
b) the velocity with which it leaves the parallel plate apparatus, inboth magnitude and direction.

Homework Equations



I'm not sure which are relavent. I tried in corporting all motion equations.

The Attempt at a Solution



There are so many ways I tried to solve this question

I already know the answer to it, but it seems impossible to get it.

0.41m
and 8x10^7m/s (right5down)

I don't expect you to solve them all for me (although it would be much helpful) , but please help me start in the right direction.

Thank you
 
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  • #2
First of all find the time taken by the electron to cover 10 cm.
Find the electric field between the plates. Then force on the electron. Using mass of the electron, find the acceleration of it. Now treat the electron as a projectile,and find the vertical deflection.
 
  • #3
okay, what do you the electric field?

the intensity? v/d?
 
  • #4
Yes. v/d.
What is F? What is a?
 
  • #5
okay i got the answer to a) finally! :D

now b... hm...
 
  • #6
how would i start this one.?

i tried..

v2^2=v1^2+2ad
 
  • #7
Initially there is no vertical velocity. SO vi = 0.
Find the time t taken by the electron to travel 10 cm.
Find the vertical velocity after t s.
Horizontal velocity remains constant. Hence find the resultant velocity.
 
  • #8
i solved finally, thank you.
 

FAQ: Electric Fields Question (deflection? :S? and more)

What is an electric field?

An electric field is a physical quantity that describes the influence of electric forces on a charged particle. It is represented by a vector, with both magnitude and direction, and is created by the presence of electric charges.

How does an electric field cause deflection?

An electric field causes deflection by exerting a force on charged particles. When a charged particle enters an electric field, it will experience a force in the direction of the field if it has the same charge as the field, and in the opposite direction if it has the opposite charge. This force causes the particle to change its direction of motion, resulting in deflection.

What factors affect the magnitude and direction of deflection in an electric field?

The magnitude and direction of deflection in an electric field are affected by the strength of the field, the charge of the particle, and the mass of the particle. The strength of the field and the charge of the particle determine the force exerted on the particle, while the mass of the particle affects its ability to resist the force and therefore the degree of deflection.

How is the direction of deflection determined in an electric field?

The direction of deflection in an electric field is determined by the direction of the electric field itself and the charge of the particle. If the particle has the same charge as the field, it will be deflected in the direction of the field. If the particle has the opposite charge, it will be deflected in the opposite direction of the field.

What are some real-world applications of electric field deflection?

Electric field deflection has many real-world applications, including in cathode ray tubes (CRTs) used in older televisions and computer monitors, particle accelerators in scientific research, and mass spectrometry in chemistry. It is also used in electronic devices such as oscilloscopes and electron microscopes.

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