Electric Potential and Field Calculations for Point Charges on the x-Axis

In summary: Also, for the electric field, it would be:E = (kQ)/r^2It is not. Just use some values to check it: is the distance between x0=3m and x1=4m the sum of both (7m)?And don't forget the other r.Also, for the electric field, it would be:E = (kQ)/r^2In summary, the question involves a point charge of -11.5nC and a point charge of +24.6nC that are 14.0cm apart on the x-axis. The electric potential at the point where the electric field is zero is 1.58E2 V. To find the magnitude
  • #1
rockerdude1210
20
0

Homework Statement



A -11.5nC point charge and a +24.6nC point charge are 14.0cm apart on the x-axis.

a) What is the electric potential at the point on the x-axis where the electric field is zero? - The answer is 1.58E2 V

b) What is the magnitude of the electric field at the two points on the x-axis where the electric potential is zero? (Input your answers in order of increasing distance from the negative point charge.)

I figured out a, but I wasn't able to get b. There should be two answers for b.


Homework Equations



E=(kQ)/r^2 - equation 1

V=(kQ)/r - equation 2



The Attempt at a Solution



I know what to do but I wasn't able to execute it. I think you have to find the value of r in equation 2 where it equals 0 and then sub that into equation 1. I'm not sure how to do this though, any help would be appreciated!
 
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  • #2
V=(kQ)/r - equation 2
This is the potential for one charge only. You have two different charges.

I think you have to find the value of r in equation 2 where it equals 0 and then sub that into equation 1.
Right. That will work as soon as you get the right formula for your potential.

Keep in mind that the electric field has a direction - don't just add its magnitude, pay attention to the signs.
 
  • #3
mfb said:
This is the potential for one charge only. You have two different charges.

Right. That will work as soon as you get the right formula for your potential.

Keep in mind that the electric field has a direction - don't just add its magnitude, pay attention to the signs.


Oh, sorry, I meant:

(kQ1)/r + (kQ2)/r - equation 2.

and the field for the negative charge would be towards it and the field for the positive charge would be away from it. But, I still don't know what to do with that information.
 
  • #4
(kQ1)/r + (kQ2)/r - equation 2.
That is not right, the distance is different, too.

Oh, and please describe your problem in the topic. "Physics question" is pointless in a physics forum. I changed it to "Electric potential and field" and moved the thread to the right subforum.
 
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  • #5
mfb said:
That is not right, the distance is difference, too.

Oh, and please describe your problem in the topic. "Physics question" is pointless in a physics forum. I changed it to "Electric potential and field" and moved the thread to the right subforum.

What would it be then? I really can't figure it out :S

And okay
 
  • #6
If you are at a position x0 and have a charge at position x1, what is the distance to the charge?
 
  • #7
mfb said:
If you are at a position x0 and have a charge at position x1, what is the distance to the charge?

it would be x0 + x1
so, would that make the equation this:

(kQ1)/r + (kQ2)/ ( x0 + x1 )
 
  • #8
rockerdude1210 said:
it would be x0 + x1
It is not. Just use some values to check it: is the distance between x0=3m and x1=4m the sum of both (7m)?

And don't forget the other r.
 

FAQ: Electric Potential and Field Calculations for Point Charges on the x-Axis

What is electric potential?

Electric potential is the amount of electric potential energy that a unit charge has at a specific point in an electric field. It is measured in volts (V).

What is an electric field?

An electric field is a region of space around an electrically charged particle or object in which other charged particles experience a force. It is created by the presence of electric charges and is measured in volts per meter (V/m).

How are electric potential and electric field related?

Electric potential and electric field are closely related. The electric field at a point is equal to the change in electric potential per unit distance in the direction of the field. In other words, the electric field is the gradient of the electric potential.

What is the difference between electric potential and electric potential energy?

Electric potential is the potential energy per unit charge, while electric potential energy is the total potential energy of a charged particle or object in an electric field. Electric potential is a property of the electric field, while electric potential energy is a property of the charged particle or object.

How is electric potential and electric field used in practical applications?

Electric potential and electric field are used in many practical applications, such as in the design and operation of electronic devices, power transmission and distribution systems, and medical equipment. They are also used in fields such as electrostatics, electromagnetism, and electrochemistry.

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