- #1
boris16
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hiya
1)
Some quotes from physics tutorial site:
Wouldn't it be more correct if instead we said:
*The kinetic energy charge has was transformed from charge's potential energy, and this kinetic energy gets lost as charge goes trough light bulb?*
The way I understand it, as electron moves trough electric field its potential energy is transformed into kinetic energy ( same way as potential energy of object falling towards the ground is transformed into kinetic energy W[k] ). And when this W[k] goes trough lightbulb, W[k] gets transformed into other types of energy. So, if two charged parallel plates are 1 meter apart and electron is put inside their EF at point A(near negatively charged plate), then once electron travels half the distance between the plates it will loose half of its potential energy
In short, loss of potential energy depends on how much closer a charge is to its final destination ( compared to its initial position ) and not how much of this charge's kinetic energy a device like lightbulb has transformed into other kinds of energies ( light etc ). Correct?
2)
The following text
also makes it sound as if potential energy is not location dependent, but instead it solely depends on where the devices such as ligh bulb are located!
Let me explain what I mean:
Note - green thingy represents a light bulb and red is wire. The two boxes are positive and negative terminals.
http://img367.imageshack.us/img367/3802/a4rc.jpg
If potential difference is defined as how much closer charge is at point B ( compared to point A ) to its final destination ( final destination being positive terminal ), then how can there be potential loss resulting from current going trough the light bulb? I know there is loss of energy due to electrons passing trough the lightbulb, but since charge in point B is not at all closer to positive terminal then in point A, the kinetic energy ( the one electrons lost while going trough light ball ) was not created from potential energy. Actually, I'd say that no potential energy charge posseses has yet been transformed into kinetic energy?
thank you
1)
Some quotes from physics tutorial site:
The above all makes sense. But this is where I get lost:
Electric potential is a location dependent quantity which expresses the amount of potential energy per unit of charge at a specified location.
Suppose we move positive test charge within a uniform electric field from location A to location B as shown in the following diagram :
http://img367.imageshack.us/img367/6707/u9l1c28fs.gif
In moving the charge against the electric field from location A to location B, work will have to be done on the charge by an external force. The work done on the charge changes its potential energy to a higher value; and the amount of work which is done is equal to the change in the potential energy. As a result of this change in potential energy, there is also a difference in electric potential between locations A and B. This difference in electric potential is represented by the symbol V and is formally referred to as the electric potential difference
As depicted in the diagram below, a charge carrier traversing the external circuit from A to H passes through three different light bulbs. Each light bulb results in a loss of electric potential for the charge.
Wouldn't it be more correct if instead we said:
*The kinetic energy charge has was transformed from charge's potential energy, and this kinetic energy gets lost as charge goes trough light bulb?*
The way I understand it, as electron moves trough electric field its potential energy is transformed into kinetic energy ( same way as potential energy of object falling towards the ground is transformed into kinetic energy W[k] ). And when this W[k] goes trough lightbulb, W[k] gets transformed into other types of energy. So, if two charged parallel plates are 1 meter apart and electron is put inside their EF at point A(near negatively charged plate), then once electron travels half the distance between the plates it will loose half of its potential energy
In short, loss of potential energy depends on how much closer a charge is to its final destination ( compared to its initial position ) and not how much of this charge's kinetic energy a device like lightbulb has transformed into other kinds of energies ( light etc ). Correct?
2)
The following text
As depicted in the diagram below, a charge carrier traversing the external circuit from A to H passes through three different light bulbs. Each light bulb results in a loss of electric potential for the charge.
also makes it sound as if potential energy is not location dependent, but instead it solely depends on where the devices such as ligh bulb are located!
Let me explain what I mean:
Note - green thingy represents a light bulb and red is wire. The two boxes are positive and negative terminals.
http://img367.imageshack.us/img367/3802/a4rc.jpg
If potential difference is defined as how much closer charge is at point B ( compared to point A ) to its final destination ( final destination being positive terminal ), then how can there be potential loss resulting from current going trough the light bulb? I know there is loss of energy due to electrons passing trough the lightbulb, but since charge in point B is not at all closer to positive terminal then in point A, the kinetic energy ( the one electrons lost while going trough light ball ) was not created from potential energy. Actually, I'd say that no potential energy charge posseses has yet been transformed into kinetic energy?
thank you
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