Equivalent of tan(t) near Pi/2

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In summary, tan(t) is infinite near Pi/2 and is related to Pi/2 as the opposite and adjacent sides of a right triangle become equal, resulting in an infinite ratio. Tan(t) is undefined at Pi/2 due to a vertical asymptote and cannot be solved for 0 at this point. The graph of tan(t) near Pi/2 appears to have a vertical line at (Pi/2, infinity) and becomes steeper as t approaches Pi/2.
  • #1
penguin007
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Homework Statement



How can you get an equivalent of tan(t) in the neighborhood of Pi/2?

Homework Equations



the answer is 1/(Pi/2-t)

The Attempt at a Solution



I tryed to use a Taylor's expansion but the problem is that tan(Pi/2) does not exist.



Thanks for your help!
 
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  • #2
How about doing a Taylor expansion for tan^(-1) t instead?
 
  • #3
cot(pi/2) exists. And tan(x)=1/cot(x).
 
  • #4
thanks guys
 

FAQ: Equivalent of tan(t) near Pi/2

What is the equivalent of tan(t) near Pi/2?

The equivalent of tan(t) near Pi/2 is infinite. As the value of t approaches Pi/2, the value of tan(t) also approaches infinity.

How is tan(t) related to Pi/2?

Tan(t) is the ratio of the opposite side to the adjacent side in a right triangle. When t is Pi/2, the opposite side of the triangle becomes equal to the adjacent side, resulting in an infinite ratio.

Why is tan(t) undefined at Pi/2?

Tan(t) is undefined at Pi/2 because the tangent function has a vertical asymptote at this point. This means that the function approaches infinity as t gets closer to Pi/2 from both sides.

Can Pi/2 be a solution to tan(t) = 0?

No, Pi/2 cannot be a solution to tan(t) = 0 because the tangent function is never equal to 0 at this point. Instead, the function approaches infinity.

How does the graph of tan(t) look near Pi/2?

Near Pi/2, the graph of tan(t) appears to have a vertical line going through the point (Pi/2, infinity) due to the vertical asymptote. The graph also becomes steeper and steeper as t approaches Pi/2 from both sides.

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