Expectation of an Hermitian operator is real.

In summary, an operator is considered Hermitian if it is equal to its own conjugate transpose. Its expectation can be determined by taking the inner product of the state vector with the operator applied to it, and it will always be a real number because of the properties of inner products. The expectation of an Hermitian operator is closely related to measurement outcomes, and while it cannot be negative, it can be zero.
  • #1
noospace
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Homework Statement



WTS [itex] \langle \hat{A} \rangle = \langle \hat{A} \rangle^\ast [/itex]

The Attempt at a Solution



[itex]\langle \hat{A} \rangle^\ast = \left(\int \phi_l^\ast \hat{A} \phi_m dx\right)^\ast=\left(\int (\hat{A}\phi_l)^\ast \phi_m dx\right)^\ast= \int \phi_m^\ast \hat{A}\phi_l dx[/itex]. So far, I haven't seen why this equals [itex]\int \phi_l^\ast \hat{A} \phi_m dx[/itex].

Thanks
 
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use same fields to show
eg. [tex](\Psi, A\Psi) = (\Psi, A\Psi)^*[/tex]
 

FAQ: Expectation of an Hermitian operator is real.

What does it mean for an operator to be Hermitian?

An operator is considered Hermitian if it is equal to its own conjugate transpose. In other words, the operator remains unchanged when its elements are switched from complex numbers to their complex conjugates.

How is the expectation of an Hermitian operator determined?

The expectation of an Hermitian operator is determined by taking the inner product of the state vector with the operator applied to that vector. This can be represented mathematically as ⟨A⟩ = ⟨ψ|A|ψ⟩, where A is the Hermitian operator and ψ is the state vector.

Why is the expectation of an Hermitian operator always a real number?

This is because the inner product of a state vector with its complex conjugate is always a real number. Since the expectation of an Hermitian operator involves taking the inner product of the state vector with the operator applied to it, the result will always be a real number.

How is the expectation of an Hermitian operator related to measurement outcomes?

The expectation of an Hermitian operator is a key concept in quantum mechanics and is closely related to measurement outcomes. The squared magnitude of the expectation value represents the probability of obtaining a certain measurement outcome when the operator is measured in that state.

Can the expectation of an Hermitian operator be negative?

No, the expectation of an Hermitian operator cannot be negative. This is because the squared magnitude of the expectation value represents the probability of obtaining a certain measurement outcome, and probabilities cannot be negative. However, the expectation value can be zero, indicating a zero probability of obtaining a certain measurement outcome.

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