Exploring the Electric Field in a Solenoid

The electric field at every point on the surface would have to be the same.In summary, the conversation discusses the relationship between electric and magnetic fields in a solenoid. It is explained that the electric field around a current carrying wire is zero, and this is due to the formula E=Q/4pi_r^2. However, it is mentioned that this formula is missing the \epsilon_0 term, and it is clarified that it is the formula for E from a point charge. The discussion then shifts to the relevance of this formula in a solenoid experiment, and it is questioned what the B/r^2 and B/r stand for in this context. The conversation ends with the understanding that in a current carrying wire,
  • #1
Googl
111
1
Can we find an electric field in a solenoid? Just a little confused
 
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  • #2
The E field around a current carrying wire is zero.
 
  • #3
Thanks,

Is there any reason why?
 
  • #4
My teach is telling me that E=Q/4pi_r^2 is directly proportional to B/r^2

Does that make sense. The first formula is the formula used to find the electric field.
 
  • #5
Googl said:
E=Q/4pi_r^2

What does this have to do with a solenoid? This looks like the formula for E from a point charge except it's missing an [itex]\epsilon_0[/itex].
 
  • #6
Yes it is the formula E from a point charge.

What would the B/r^2 stand for in a solenoid experiment? I mean what would you use that for to find what?

And what about B/r

Thanks.
 
  • #7
In a current carrying wire the sum of the charge in side would be zero. You could make a Gauss surface around the wire.
 

FAQ: Exploring the Electric Field in a Solenoid

What is an electric field in a solenoid?

An electric field in a solenoid is a region in which electrically charged particles experience a force due to the presence of an electrically charged object or source. In a solenoid, the electric field is created by the movement of electric charges through the wire coils.

How is the electric field in a solenoid calculated?

The electric field in a solenoid can be calculated using the equation E = -N(dΦ/dt), where E is the electric field strength, N is the number of turns in the solenoid, and dΦ/dt is the change in magnetic flux over time.

What factors affect the strength of the electric field in a solenoid?

The strength of the electric field in a solenoid is affected by several factors, including the number of turns in the solenoid, the current flowing through the solenoid, and the material of the wire used in the solenoid. Additionally, the length and diameter of the solenoid can also affect the strength of the electric field.

What is the direction of the electric field in a solenoid?

The direction of the electric field in a solenoid is parallel to the axis of the solenoid. This means that the electric field lines run parallel to the direction of the coil.

What are some real-life applications of the electric field in a solenoid?

The electric field in a solenoid has many practical applications in everyday life. Some examples include electromagnets used in MRI machines, loudspeakers, and electric motors. Solenoids are also used in various household appliances, such as washing machines and refrigerators.

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