Expression for voltage across resistor in circuit

In summary: Vx simplifies to a form that is approximately independent of R3.In summary, the question is asking for an expression for the voltage across R3 in terms of V0, R1, R2, and R3, and under what condition is this voltage approximately independent of the value of R3. This can be found by modifying the basic potential divider equation to include R3 and then simplifying it.
  • #1
leroyjenkens
616
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Homework Statement


Write an expression for the voltage across R3 in terms of V0, R1, R2, and R3. Under what condition is the voltage across R3 approximately independent of the value of R3?


Homework Equations


I uploaded a picture.
I think Req = R1 + R2...
and 1/Req = 1/R1 + 1/R2...
Are what I need.


The Attempt at a Solution


Best thing I could think of doing was adding R2 and R3, and then add R1 to get this:

1/R2+R3 + R1, but I don't know how to include the voltage.

And I have no idea what it means by what condition is the voltage across R3 approximately independent of the value of R3.
 

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  • #2
leroyjenkens said:

Homework Statement


Write an expression for the voltage across R3 in terms of V0, R1, R2, and R3. Under what condition is the voltage across R3 approximately independent of the value of R3?

Homework Equations


I uploaded a picture.
I think Req = R1 + R2...
and 1/Req = 1/R1 + 1/R2...
Are what I need.

There seems to be a confusion, common among many people, in your calculation of Req: Identifying which resistors are in series and which are in parallel. What helped me was watching these two videos: http://www.youtube.com/watch?v=0vqmQuo03Ss&list=PL4F8106B5158CB89E&index=13

In fact, the entire playlist was helpful on the whole subject of circuit analysis!

leroyjenkens said:

The Attempt at a Solution


Best thing I could think of doing was adding R2 and R3, and then add R1 to get this:

1/R2+R3 + R1, but I don't know how to include the voltage.

While finding Req first and finding the voltage drop across R3 from there is a valid method (and I suggest you work it out for learning purposes), also consider the application of Kirchoff's Voltage Law

leroyjenkens said:
And I have no idea what it means by what condition is the voltage across R3 approximately independent of the value of R3.

Hmmm... I'm not exactly sure what this means either. However, I would suggest to consider how the behavior of voltages and currents differ in purely series and purely parallel circuits.
 
  • #3
leroyjenkens said:

Homework Statement


Write an expression for the voltage across R3 in terms of V0, R1, R2, and R3. Under what condition is the voltage across R3 approximately independent of the value of R3?


Homework Equations


And I have no idea what it means by what condition is the voltage across R3 approximately independent of the value of R3.

What would happen if R1 << R3 or R2 << R3?
 
  • #4
leroyjenkens said:
And I have no idea what it means by what condition is the voltage across R3 approximately independent of the value of R3.

Without R3, you can see R1 and R2 form a potential divider, dividing that potential V0. R3 could represent a load that you wish to connect, to be powered by that smaller potential set by R1 and R2 and the voltage source.

As you know, the fact of connecting R3 will change the potential divider so the equation for the voltage across R2 must now involve a modification to include the value of R3.

If we denote the voltage across R2 as Vx, then your first task is to start with the basic potential divider equation:
Vx = R2/(R1+R2).V0

and modify it to include R3, since R3 appears in parallel with R2. (At this stage, you have made no simplifying assumptions or approximations.)

Your second task then becomes more of a mathematical one ...
 
  • #5


I would like to thank you for providing a clear statement of the problem and the equations that you have attempted to use to solve it. The expression for the voltage across R3 can be written as V3 = V0 * (R3 / (R1 + R2 + R3)). This can be derived by using Kirchhoff's Voltage Law, which states that the sum of all voltages in a closed loop must equal zero. In this case, the voltage across R3 is equal to the voltage across R1 and R2 combined, which is then multiplied by the ratio of R3 to the total resistance (R1 + R2 + R3).

The condition for the voltage across R3 to be approximately independent of its value is when R3 is much larger than R1 and R2. This can be seen from the expression above, where as R3 approaches infinity, the voltage across R3 becomes equal to V0, regardless of the values of R1 and R2. This is because as R3 becomes larger, it becomes the dominant resistor in the circuit, and the voltage drop across it becomes the main factor in determining the voltage across R3.
 

FAQ: Expression for voltage across resistor in circuit

What is the equation for calculating the voltage across a resistor in a circuit?

The equation for calculating the voltage across a resistor in a circuit is V = IR, where V is voltage (measured in volts), I is current (measured in amperes), and R is resistance (measured in ohms).

How does the voltage across a resistor change with increasing or decreasing resistance?

The voltage across a resistor is directly proportional to the resistance. This means that as the resistance increases, the voltage across the resistor will also increase. Similarly, as the resistance decreases, the voltage across the resistor will decrease.

Can the voltage across a resistor be negative?

No, the voltage across a resistor cannot be negative. Voltage is a measure of the potential difference between two points in a circuit, and a resistor can only resist the flow of current, not create a negative voltage.

How does the voltage across a resistor change in a series circuit?

In a series circuit, the voltage across each resistor is equal to the total voltage of the circuit. This means that the voltage across a resistor will not change as more resistors are added in series.

How does the voltage across a resistor change in a parallel circuit?

In a parallel circuit, the voltage across each resistor will be the same. This is because the voltage in a parallel circuit is divided among the different branches, but the total voltage across the circuit remains the same.

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