- #1
kurious
- 641
- 0
If you take the equation for the radius of the event horizon of a black hole and imagine that the mass of a proton is made from lots of tiny masses that form a mini black hole, and that the charge of the proton is made from mini charges that also form a black hole then:
G M/ 3 C^ 2 = K Q / 3 v ^ 2
putting in values for G the gravitational constant , 6.6 x 10^ -11, k the coulomb constant 9.9 x 10 ^ -9, M the mass = 1.6 x 10 ^ -27,
Q the electric charge = 1.6 x 10 ^ -19, C the speed of light = 3 x 10^8 and v is a new unknown speed, the value of v is 10^23 metres per second!
Whether or not you need nuclear power to get to this speed I couldn't say!
G M/ 3 C^ 2 = K Q / 3 v ^ 2
putting in values for G the gravitational constant , 6.6 x 10^ -11, k the coulomb constant 9.9 x 10 ^ -9, M the mass = 1.6 x 10 ^ -27,
Q the electric charge = 1.6 x 10 ^ -19, C the speed of light = 3 x 10^8 and v is a new unknown speed, the value of v is 10^23 metres per second!
Whether or not you need nuclear power to get to this speed I couldn't say!