- #1
physics_ash82
- 18
- 0
Im supposed to find the critical numbers for the function:
F(x)= x^3-12x^2
I think I did it right I just needed some reassurance, I got
F'(x)= 3x^2-24
=3x(x-8)
=3x=0 and x-8=0
so the critcal numbers are x=0 and x=8 I think:shy: I hope someone can tell me if I did this right
Thanks
ash
F(x)= x^3-12x^2
I think I did it right I just needed some reassurance, I got
F'(x)= 3x^2-24
=3x(x-8)
=3x=0 and x-8=0
so the critcal numbers are x=0 and x=8 I think:shy: I hope someone can tell me if I did this right
Thanks
ash