Find the effective area required to build such a capacitor

In summary, the conversation involves discussing the possibility of building a 1 Farad capacitor that is only a few centimeters long using Strontium Titanate as the dielectric material. The minimum gap necessary for a maximum voltage of 5 volts is being speculated, as well as the effective area required for such a capacitor. The challenge is to fit this area into a small volume.
  • #1
euphrates
2
0

Homework Statement



One can buy 1 Farad capacitors which are only a few centimeters long. Speculate
on how you can build such a capacitor. Assuming that you are using Strontium
Titanate as the dielectric find the minimum gap for a maximum voltage of 5 volts.
Find the effective area required to build such a capacitor. How can you put this area
into a volume that is only a few centimeters

Homework Equations


C=Q/V
C=EoA/d

The Attempt at a Solution


to find the minimum gap, i think we can start from dielectric strength??
 
Last edited:
Physics news on Phys.org
  • #2

The Attempt at a Solution


Aren't you forgetting something??
 
  • #3
i don't have any idea about how to solve that problem so a little help
 
  • #4
You need to start by looking at the equation for the capacitance of a capacitor with a dielectric. The equation you listed is for capacitance with no dielectric.
 

FAQ: Find the effective area required to build such a capacitor

What is the effective area required to build a capacitor?

The effective area required to build a capacitor depends on several factors such as the dielectric material being used, the desired capacitance value, and the voltage rating. In general, the effective area is directly proportional to the capacitance and inversely proportional to the dielectric constant and voltage rating.

How can I calculate the effective area of a capacitor?

The effective area of a capacitor can be calculated using the following formula: A = C * d/V, where A is the effective area, C is the capacitance, d is the distance between the plates, and V is the voltage rating. This formula assumes a parallel plate capacitor with a uniform electric field.

Can the effective area be reduced for a given capacitance?

Yes, the effective area of a capacitor can be reduced by either increasing the distance between the plates or by using a dielectric material with a higher dielectric constant. However, these adjustments may also affect the capacitance and voltage rating of the capacitor.

How does the shape of a capacitor affect the effective area?

The shape of a capacitor can significantly impact the effective area. For example, a cylindrical capacitor will have a smaller effective area compared to a parallel plate capacitor with the same capacitance and voltage rating.

Are there any limitations to the effective area of a capacitor?

Yes, there are certain limitations to the effective area of a capacitor. This includes the physical size constraints, the availability of suitable dielectric materials, and practical manufacturing limitations. Additionally, increasing the effective area beyond a certain point may not result in a significant increase in capacitance due to the diminishing returns of the formula.

Back
Top