- #1
wolves5
- 52
- 0
A wooden block of mass m = 9 kg starts from rest on an inclined plane sloped at an angle q from the horizontal. The block is originally located 5m from the bottom of the plane. If the block, undergoing constant acceleration down the ramp, slides to the bottom in t = 2 s, and q = 30°, what is the magnitude of the kinetic frictional force on the block?
For this problem, the kinetic frictional force is = to (coefficient frictional force)(normal force). However, there is no coefficient frictional force in this problem. How do I get that? I calculated the normal force to be 88.2. I did F=ma. F=(9 kg) (9.81 m/s2), and got 88.2 N. How do I find the frictional force?
For this problem, the kinetic frictional force is = to (coefficient frictional force)(normal force). However, there is no coefficient frictional force in this problem. How do I get that? I calculated the normal force to be 88.2. I did F=ma. F=(9 kg) (9.81 m/s2), and got 88.2 N. How do I find the frictional force?