Finding Fourier extension and if it converges

In summary, the problem asks to extend the function f(x) = sin(x)/x periodically and determine if the Fourier series will converge at x=0. The Fourier coefficients are given as ao = 2Si(pi)/pi, an = (-Si((n-1)pi) + Si((n+1)pi))/pi, and bn = 0. The Fourier series is then computed as f(x) = 1/\pi*Si(\pi)+\sum_{1}^{\infty }1/\pi(-Si((n-1)\pi) + Si((n+1)\pi). It is unclear if this series will converge to the original function, and the sine integral function may be needed to simplify
  • #1
Weilin Meng
25
0

Homework Statement


Let f(x) = sin(x)/x for |x| <= pi with the obvious definition at x = 0

Extend it periodically. Will the Fourier series converge at x=0?

Homework Equations


Fourier coefficients:

ao = [tex]1/\pi \int_{-\pi}^{\pi} (sin(x)/x)[/tex]

an = [tex]1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * cos(nx)[/tex]

bn = [tex]1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * sin(nx)[/tex]

The Attempt at a Solution



ao = [tex]1/\pi \int_{-\pi}^{\pi} (sin(x)/x)[/tex] = 2Si(pi)/pi

an = [tex]1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * cos(nx)[/tex] = (-Si((n-1)pi) + Si((n+1)pi))/pi

bn = [tex]1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * sin(nx)[/tex] = 0

So the Fourier series will be:
[tex]f(x)=1/\pi*Si(\pi)+\sum_{1}^{\infty }1/\pi(-Si((n-1)\pi) + Si((n+1)\pi)[/tex]

at x=0 because cos(n(0)) = 1

I figured that:
[tex]\sum_{1}^{\infty }1/\pi(-Si((n-1)\pi) + Si((n+1)\pi)[/tex]
Will converge to zero and we get f(x) = si(pi)/pi...

I don't know what si(pi)/pi is but I don't think that converges to 1 as sin(x)/x does at x=0...did i mess up anything?
 
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  • #2
bump, nobody yet? Am I not providing anything?
 
  • #3
I'm not too familiar with the sine integral function, but seeing how your summand consists of a difference of two evaluations (and the arguments have a fixed difference! Surely that will help simplify whatever you do), maybe there's a "difference of si's" identity you could use? Maybe the difference could be expressed usefully as a differential approximation, or even a full blown Taylor series. Or, maybe there's another way to simplify the infinite sum...
 
  • #4
Ok, since you are bumping, do you really need to work out the Fourier series to figure out where it converges? Don't you have theorems about where it converges to save you this pain?
 
  • #5
Dick said:
Ok, since you are bumping, do you really need to work out the Fourier series to figure out where it converges? Don't you have theorems about where it converges to save you this pain?

Haha, I don't know if I mentioned, but this is from a PDE course, and we are asked to compute the Fourier series and see if it converges with the original function...The course doesn't assume a huge background in math except some knowledge in ODE's, linear algebra and multi-calc. Unfortunately I have no more memory of how to do taylor or power series, but I am sure that the question does not ask for that.

Also I did not know about the Si function until I put it in an integrator..I admit that the professor usually goes crazy when coming up with his own problems...

anywho the question asks whether it converges or not...so for all I know I could be right in that it does not converge. Can anybody confirm this?
 

FAQ: Finding Fourier extension and if it converges

What is Fourier extension?

Fourier extension is a mathematical technique used to extend a function defined on a finite interval to a periodic function on the entire real line. This allows us to study the properties of the function over a larger interval and can provide insights into its behavior.

How is Fourier extension used?

Fourier extension is commonly used in signal processing, image processing, and other areas of science and engineering to analyze and represent periodic signals and functions. It is also used in the study of differential equations and other areas of mathematics.

What is the Fourier series?

The Fourier series is a mathematical representation of a function as an infinite sum of sines and cosines. It is closely related to Fourier extension, as it allows us to express a periodic function in terms of its Fourier coefficients, which can then be used to extend the function to a larger interval.

Does the Fourier extension always converge?

No, the Fourier extension may not always converge. It depends on the properties of the function being extended and the convergence of its Fourier series. In some cases, the Fourier series may not converge to the original function, resulting in a discontinuous or non-periodic extension.

How do you determine if the Fourier extension converges?

The convergence of the Fourier extension can be determined by examining the Fourier coefficients of the function being extended. If the coefficients follow a certain pattern, such as decreasing in magnitude, the Fourier series will converge and the extension will be continuous. However, if the coefficients do not follow a pattern, the extension may not converge.

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