Finding Intersections: Solving 4x-x^2=3

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In summary, to find the intersections of two functions, you equate them together and solve for x. If x is a complicated expression, a computer may be needed for an approximate answer. If the functions are implicit, more work is required to get one equation in terms of the other and solve for one variable, possibly using a root-finding algorithm.
  • #1
jmanna98
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Can someone please help me with some algebra. I need to find the intersections of 2 functions so that I can find the volume using cylindrical shells and I have become pretty rusty when graphing the functions. When setting the functions equal to each other I get:

4x-x^2=3

Now I forget, do I just try solving for x (which I can't figure out how to do) or can I bring everything over to one side and set it equal to zero ...(or is that just going to find the roots?)

How should I do this?
 
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  • #2
Hey jmanna98 and welcome to the forums.

To find the intersection of two functions you just equate them together. Doing this depends on the representation of the function.

For example if you have two functions that are represented as y = bla1 and y = bla2 then basically you just use the fact that bla1 = blah2 and then solve for x. If x is a complicated expression then you will need to use a computer to get an approximate answer.

If however it is implicit (like say x^2y + x^5 x SQRT(y) = 3), then you have to do a bit more work, but the idea is the same: get one equation in terms of the other, rearrange and then solve for one variable which might mean using a root-finding algorithm).
 
  • #3
Thanks for that. Much appreciated.
 

FAQ: Finding Intersections: Solving 4x-x^2=3

What is the best way to solve 4x-x^2=3?

The best way to solve this equation is by setting it equal to zero and using the quadratic formula. By setting it equal to zero, we can find the x-intercepts or the points where the graph of the equation intersects with the x-axis. The quadratic formula, which is (-b±√(b^2-4ac))/2a, can be used to solve for x.

Can I solve this equation using factoring?

Yes, this equation can be solved using factoring. However, it may not always be the most efficient method, especially if the equation is not easily factorable. In this case, using the quadratic formula may be a better option.

Is there more than one solution to this equation?

Yes, there can be more than one solution to this equation. Since it is a quadratic equation, there can be two possible solutions, also known as roots. However, it is also possible for there to be only one solution or no real solutions at all.

Can I solve this equation graphically?

Yes, this equation can be solved graphically by graphing both sides of the equation and finding the points where the graphs intersect. The x-coordinate of the points of intersection will be the solutions to the equation.

Are there any special techniques for solving this type of equation?

One special technique for solving this type of equation is completing the square. This method involves manipulating the equation to create a perfect square trinomial, which can then be easily solved. However, it is not always necessary to use this method and may be more time-consuming compared to other methods such as factoring or using the quadratic formula.

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