Finding x,y,z for ∇f Pointing in +z Direction

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In summary, the gradient of the function f(x,y,z) = x2 + y2 + z2 is (2x,2y,2z) and in order for it to point in the positive z direction, z must be any positive number while x and y are both equal to 0.
  • #1
chemphys1
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f(x,y,z) = x2 + y2 + z2

which values of x,y,z does ∇f point in the positive z directionok so I know ∇f = i ∂/∂x + j ∂/∂y + k ∂/∂z

which turns out to be

∇f = 2x i + 2y j + 2z k

but how am I finding values so that z points in the positive direction? what does that even mean?
∇f is gradient, could it have specified x direction or y direction, if so what would differ about how to answer the question?

any help/explanation much appreciated
 
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  • #2
I guess they mean that a vector points in the positive ##z##-direction if it is of the form ##(0,0,k)## for ##k>0##. Does that help?
 
  • #3
micromass said:
I guess they mean that a vector points in the positive ##z##-direction if it is of the form ##(0,0,k)## for ##k>0##. Does that help?

I don't recognise this kind of question, how would I go about finding this vector?
 
  • #4
chemphys1 said:
I don't recognise this kind of question, how would I go about finding this vector?

For which ##(x,y,z)## is the gradient ##(2x,2y,2z)## of the form ##(0,0,k)## for ##k>0##.
 
  • #5
micromass said:
For which ##(x,y,z)## is the gradient ##(2x,2y,2z)## of the form ##(0,0,k)## for ##k>0##.

is it as simple as follows:
x = 0
y= 0
z = any positive integer?
 
  • #7
chemphys1 said:
is it as simple as follows:
x = 0
y= 0
z = any positive integer?

Almost. You mean any positive number.
 
  • #8
Thank you for the help, it really is appreciated!
 

FAQ: Finding x,y,z for ∇f Pointing in +z Direction

What is the purpose of finding x,y,z for ∇f pointing in +z direction?

The purpose of finding x,y,z for ∇f pointing in +z direction is to determine the directional derivative of a function f in the direction of the positive z-axis. This information can be used to analyze the rate of change of the function in that direction.

How do you find x,y,z for ∇f pointing in +z direction?

To find x,y,z for ∇f pointing in +z direction, you can use the formula ∇f = (∂f/∂x, ∂f/∂y, ∂f/∂z) and set the z-component (∂f/∂z) to a positive value. Then, solve for x and y using the other two components (∂f/∂x and ∂f/∂y).

What does the vector ∇f represent in this context?

In this context, the vector ∇f represents the gradient of the function f. It is a vector that points in the direction of the greatest increase of the function at a given point and its magnitude represents the rate of change of the function in that direction.

Can you find x,y,z for ∇f pointing in +z direction for any function?

Yes, x,y,z for ∇f pointing in +z direction can be found for any differentiable function. The formula for ∇f can be applied to any function with three independent variables.

What is the significance of the positive z direction in this scenario?

The positive z direction is significant because it specifies the direction in which the directional derivative is being calculated. By setting the z-component of ∇f to a positive value, we are determining the rate of change of the function in the positive z-direction. It allows us to analyze the behavior of the function in a specific direction.

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