Finding xn as n Tends to Infinity: Q1 & Q2

  • Thread starter Mattofix
  • Start date
  • Tags
    Infinity
In summary, the conversation is about solving two questions that involve finding the limit as n tends to infinity. The first question involves proving that (1/n)log(n^2) tends to 0, and the second question involves showing that \sqrt{n}/(n+ e^{-n}) converges to 0. L'Hopital's rule is mentioned as a possible method for proving the first question.
  • #1
Mattofix
138
0

Homework Statement



2 Questions, both find xn as n tends to infinity.

http://img229.imageshack.us/img229/5154/scan0002un5.th.jpg

Homework Equations


The Attempt at a Solution



Have attempted question one but am unsure if (1/n)log(n^2) tends to 0, and if it does do i need to prove it? I don't know how to do the second q, i know that sin(expn) oscillates between -1 and 1 and exp(-n) tends to 0 as n tends to infinity
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
Yes, (1/n) log(n^2) = (2/n)log(n) goes to 0. You might prove that by looking at 2ln(x)/x^2 and using L'Hopital's rule.

As for the second one, since sin is always between -1 and 1, you really just need to show that [itex]\sqrt{n}/(n+ e^{-n})< \sqrt{n}/n[/itex] (since [itex]e^{-n}[/itex] is always positive) converges to 0.
 
  • #3
thanks :smile:
 

FAQ: Finding xn as n Tends to Infinity: Q1 & Q2

What is the concept of finding xn as n tends to infinity?

The concept of finding xn as n tends to infinity is a mathematical concept that involves analyzing the behavior of a sequence xn as the value of n increases without bound. In other words, it looks at what happens to the sequence as the number of terms in the sequence approaches infinity.

How is finding xn as n tends to infinity useful in real-world applications?

Finding xn as n tends to infinity can be useful in various real-world applications, such as analyzing the growth rate of populations, predicting the long-term behavior of financial investments, and understanding the convergence of numerical algorithms. It can also help in solving problems related to limits and derivatives in calculus.

What is the difference between a convergent and a divergent sequence?

A convergent sequence is one in which the terms of the sequence approach a specific value as n tends to infinity. In other words, the sequence has a finite limit. On the other hand, a divergent sequence is one in which the terms of the sequence do not approach a specific value and the sequence does not have a finite limit as n tends to infinity.

How do you determine if a sequence is convergent or divergent?

To determine if a sequence is convergent or divergent, you can use various techniques such as the limit comparison test, the ratio test, and the root test. These tests involve evaluating the limit of the sequence as n tends to infinity and comparing it to known convergent or divergent sequences.

Can a sequence have both convergent and divergent subsequences?

Yes, a sequence can have both convergent and divergent subsequences. This means that some terms of the sequence approach a specific value while others do not. In this case, the sequence is considered divergent as a whole, but it has both convergent and divergent subsequences.

Similar threads

Replies
5
Views
1K
Replies
2
Views
1K
Replies
24
Views
1K
Replies
5
Views
1K
Replies
23
Views
2K
Replies
5
Views
1K
Back
Top