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maximade
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Homework Statement
dy/dt=y((3t^2)-1), y(1)=-2
Homework Equations
Basic integrals
The Attempt at a Solution
integrate on both sides: dy/y=dt((3t^2)-1)
========>ln(y)=(t^3)-t+c
========>y=e^((t^3)-t+c)
========>y=e^((t^3)-t)e^(c)
I am not sure if its some e rule that I forgot but how do you get -2 from y(1), since e^C is always positive?
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