- #1
sizzleiah
- 15
- 0
Hi Friends,
I am an undergrad currently taking my first course in particle physics.
In thinking about various possible reactions, I have run across what appears to be a rather basic question: Why are reactions of the form [tex]e^- + e^+ \rightarrow \gamma \rightarrow q + q^'[/tex] where q and q' are different quarks or antiquarks, prohibited (i.e. flavor changing EM interactions)? Of course, such reactions will be followed by fragmentation.
Assuming q and q' are chosen so that charge is conserved, it seems that the answer must either come from kinematics or must be empirical. The former seems as though it might be possible to overcome in some special cases (e.g. choose the velocities of q and q' so that momentum is conserved, and this may serendipitously lead to energy conservation).
Presumably there is something trivial I am overlooking; be gentle...
I am an undergrad currently taking my first course in particle physics.
In thinking about various possible reactions, I have run across what appears to be a rather basic question: Why are reactions of the form [tex]e^- + e^+ \rightarrow \gamma \rightarrow q + q^'[/tex] where q and q' are different quarks or antiquarks, prohibited (i.e. flavor changing EM interactions)? Of course, such reactions will be followed by fragmentation.
Assuming q and q' are chosen so that charge is conserved, it seems that the answer must either come from kinematics or must be empirical. The former seems as though it might be possible to overcome in some special cases (e.g. choose the velocities of q and q' so that momentum is conserved, and this may serendipitously lead to energy conservation).
Presumably there is something trivial I am overlooking; be gentle...