- #1
Punchlinegirl
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The flywheel of a steam engine begins to rotate from rest with a constant angular acceleration of 1.33 rad/s2. It accelerates for 23.5 s, then maintains a constant angular velocity. Calculate the total angle through which the wheel has turned 48.7 s after it begins rotating.
[tex] \omega = \omega _ o + \alpha t [/tex]
[tex] \omega = 0 + 1.33(23.5)[/tex]
[tex] \omega= 31.26 [/tex]
[tex] 31.26 = \Delta \theta / \Delta t [/tex]
Solving for [tex] \theta [/tex] gave me 1522.1 rad
which wasn't right.. can someone please help me?
[tex] \omega = \omega _ o + \alpha t [/tex]
[tex] \omega = 0 + 1.33(23.5)[/tex]
[tex] \omega= 31.26 [/tex]
[tex] 31.26 = \Delta \theta / \Delta t [/tex]
Solving for [tex] \theta [/tex] gave me 1522.1 rad
which wasn't right.. can someone please help me?