For this pulley system, why is it m1g - T1-T2=m1a?

In summary: There is no force that is pulling it down. Hence apply concepts and solve the problem.In summary, the problem involves three objects with masses m1 = 66.0 kg, m2 = 37.4 kg, and m3 = 21.8 kg hanging from ropes over pulleys. The forces acting on the blocks are T1=m2g+m2a and T2=m3g+m2a. The force acting on the main block is m1g - T1-T2 = m1a, not T1+T2-m1g=m1a. It is important to consistently apply the positive-up convention and consider the expected direction of acceleration for each mass. Overthinking can make the problem more
  • #1
paki123
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4-p-047.gif

Three objects with masses m1 = 66.0 kg, m2 = 37.4 kg, and m3 = 21.8 kg are hanging from ropes that run over pulleys. What is the acceleration of m1? (Take the upward direction to be positive.)

So for the two outside blocks,

I know that the forces acting on the blocks are T1=m2g+m2a, and T2=m3g+m2a

But why in literally every break down of this problem I see, the force acting on the main block is m1g - T1-T2 = m1a, but not T1+T2-m1g=m1a?

I can't seem to get the answer when I do it with the latter force layout because I end up with a negative not belonging somewhere.
 
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  • #2
paki123 said:
I know that the forces acting on the blocks are T1=m2g+m2a, and T2=m3g+m2a

But why in literally every break down of this problem I see, the force acting on the main block is m1g - T1-T2 = m1a, but not T1+T2-m1g=m1a?

I think you have a typo in the T2 equation, which I've marked in boldface.

The difference between m1g - T1-T2 = m1a and T1+T2-m1g=m1a is just the difference between choosing the positive direction up and the positive direction down; the two left-hand sides are just negatives of one another. Be sure you're consistent in applying your positive-up convention, and consider (no math required for this part, just common sense) whether for this particular combination of weights you expect the middle mass to be accelerating upwards or downwards. Whatever the middle mass does, the end masses will have the opposite sign because they're going in the other direction.
 
  • #3
paki123 said:
4-p-047.gif

Three objects with masses m1 = 66.0 kg, m2 = 37.4 kg, and m3 = 21.8 kg are hanging from ropes that run over pulleys. What is the acceleration of m1? (Take the upward direction to be positive.)

So for the two outside blocks,

I know that the forces acting on the blocks are T1=m2g+m2a, and T2=m3g+m2a

But why in literally every break down of this problem I see, the force acting on the main block is m1g - T1-T2 = m1a, but not T1+T2-m1g=m1a?

I can't seem to get the answer when I do it with the latter force layout because I end up with a negative not belonging somewhere.

When ever you do pulley problems, follow simple basics(drawing a free body diagram) and laws. If you over think, things become more complex. Here in the given case you don't know in what direction m1/m2/m3 moves, since it is nowhere given in the question that m1 moves down and m2 and m3 move up. You have taken it for granted that m2 and m3 move up which makes m1 move down. The question i ask you here is what made you think that m1 moves down?
 

FAQ: For this pulley system, why is it m1g - T1-T2=m1a?

What is m1g in the equation?

m1g represents the weight of the object attached to the pulley system. This weight is equal to the mass of the object (m1) multiplied by the acceleration due to gravity (g). It is important to include this term in the equation because it affects the overall tension in the system.

Why are there two tension forces (T1 and T2) in the equation?

There are two tension forces because the pulley system involves two ropes. The tension in these ropes is not equal to the weight of the object, but rather it is divided between the two ropes. T1 represents the tension in the rope attached to the object, while T2 represents the tension in the other rope.

What does the minus sign (-) signify in the equation?

The minus sign indicates that the two tension forces are acting in opposite directions. This is because one rope is being pulled up while the other is being pulled down. By subtracting the two tension forces, we can determine the net force acting on the object.

What is the purpose of including the acceleration (a) in the equation?

The acceleration term allows us to calculate the acceleration of the object in the pulley system. By setting the equation equal to m1a, we can solve for the acceleration and determine how quickly the object is moving.

Can this equation be used for any pulley system?

Yes, this equation can be used for any pulley system as long as the ropes are ideal (massless and frictionless) and the pulleys are also ideal (massless and frictionless). If there is friction or the ropes/pulleys have mass, additional terms would need to be included in the equation.

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