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Homework Statement
A 30.7-kg block (m1) is on a horizontal surface, connected to a 6.3-kg block (m2) hanging vertically by a massless string. The pulley is massless and frictionless. A force of 224.9 N acts on m1 at an angle of 30.5degrees. The coefficient of kinetic friction (muk between m1 and the surface is 0.209. Determine the upward acceleration of m2.
Homework Equations
Fnetx=m*ax, Fnety=m*ay, fk=muk*Fn,
The Attempt at a Solution
I drew the free-body diagram with normal force, Fn, and gravity, m*g, and the y component of the applied Force, Fy=F*sin30.5, on the y-axis with the Fnety= Fn+Fy-m*g=0. On the x-axis I have tension from m2, T, and fk=muk*Fn, and the x component, Fx=F*cos30.5. The Fnetx=T+muk*Fn-F*cos30.5, and I don't have a numerical solution for this yet. I know from Fnety that Fn=m*g-F*sin30.5 and that I'm looking to solve for T from m2 because that will be the same T on m2 on the other side of the pulley. From there I can solve for the acceleration easily but I'm having a terrible time with eliminating variables and isolating T. Am I looking over a trig identity or a simple substitution somewhere? Any suggestions would be great, thanks.