General question about ang momentum throug word problem

In summary: The platform will keep rotating at constant angular velocity unless something (like a net torque) changes that. In summary, the person standing on the rotating platform will experience no change in angular speed when walking to the center, assuming there are no external torques acting on the system.
  • #1
Miike012
1,009
0
a person with mass m stands at the outer edge of a round platform whose radius is r and whose mass is m2. the platform is rotating at a speed of ...rad/s. Assuming the platform to be a free rotating disk, what would be its angular speed if the person walked to its center?

Then the answer book says...

L(i) = L(f) because sum(torque) = 0...

How would I know the sum of the torques is zero...? Is the paragraph said.. " Assuming the platform to be a free rotating disk..." ?
 
Physics news on Phys.org
  • #2
Miike012 said:
a person with mass m stands at the outer edge of a round platform whose radius is r and whose mass is m2. the platform is rotating at a speed of ...rad/s. Assuming the platform to be a free rotating disk, what would be its angular speed if the person walked to its center?

Then the answer book says...

L(i) = L(f) because sum(torque) = 0...

How would I know the sum of the torques is zero...? Is the paragraph said.. " Assuming the platform to be a free rotating disk..." ?

The torque being referred to is external torques (applied from outside the system under consideration, which consists of the platform and person). If there are no external torques, then the angular momentum of the system must be conserved (i.e. constant).
 
  • #3
How do I know there are no external torques? I am thinking there must be some type of torque if the body is rotating...
 
  • #4
Miike012 said:
How do I know there are no external torques? I am thinking there must be some type of torque if the body is rotating...

Well for one thing the problem statement did not mention any external torques :smile:
Presumably the platform got up to speed somehow, but we've "walked in" on the problem some time after things were arranged for us. We're presented with an already rotating platform.

Rotation does not require torque any more than velocity requires force. Remember Newton's first law.
 
  • #5


The assumption that the platform is a free rotating disk means that there are no external torques acting on the system. This is a common assumption in physics problems involving rotation. In this case, the person walking to the center of the platform would not create any additional torque on the system, so the sum of the torques would remain zero. This is why the initial angular momentum (L(i)) would be equal to the final angular momentum (L(f)).
 

FAQ: General question about ang momentum throug word problem

What is angular momentum?

Angular momentum is a measure of the rotational motion of an object. It is the product of an object's moment of inertia and its angular velocity.

How is angular momentum different from linear momentum?

Angular momentum and linear momentum are both measures of an object's motion, but they differ in the direction of the motion. Linear momentum is the product of an object's mass and its velocity, while angular momentum takes into account the object's rotation around an axis.

How do I calculate angular momentum?

Angular momentum is calculated by multiplying an object's moment of inertia, which is a measure of its resistance to rotational motion, by its angular velocity, which is the rate at which it rotates around an axis.

Can angular momentum be conserved?

Yes, according to the law of conservation of angular momentum, the total angular momentum of a system remains constant unless acted upon by an external torque.

How can I apply angular momentum to word problems?

To solve word problems involving angular momentum, you will need to use the equation L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. You may also need to apply the law of conservation of angular momentum to solve the problem.

Back
Top